Java 如何以我输入的 ASCII 码显示所需的值？
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How can I display the desired value in ASCII code inputted by me?
提问by jhoanne
I need Java code. Please help me. Example: when I enter the number in ASCII
我需要Java代码。请帮我。示例：当我以 ASCII 输入数字时
0 the output will be nul
1 for soh
2 for stx until it reaches the max number of ASCII.
Consider this code. It outputs an ASCII number. How can I reverse it?
考虑这个代码。它输出一个 ASCII 数字。我怎样才能扭转它？
String test = "ABCD";
for ( int i = 0; i < test.length(); ++i ) {
char c = test.charAt( i );
int j = (int) c;
System.out.println(j);
}
采纳答案by Jigar Joshi
import java.io.*;
import java.lang.*;
public class CharToASCII{
public static void main(String args[]) throws IOException{
BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the char:");
String str = buff.readLine();
for ( int i = 0; i < str.length(); ++i ){
char c = str.charAt(i);
int j = (int) c;// your work is done here
System.out.println("ASCII OF "+c +" = " + j + ".");
}
}
}
回答by Andreas Dolk
Just cast an integer value to char.:
只需将整数值转换为 char.：
int value = (int) 'a';
System.out.println((char) value); // prints a
If you need some literal output for ASCII values below '0', you'll need a mapping from the integer value (the ASCII number) to the literal, like this:
如果您需要一些文字输出低于 '0' 的 ASCII 值，您将需要从整数值（ASCII 数字）到文字的映射，如下所示：
String[] literals0to32 = {"NUL", "SOH", "STX", /* to be continued */ };
private static String toLiteral(int value) {
if (value < 0 || value > 255)
throw new IKnowThatIHaveToValidateParametersException();
if (value < 32)
return literals0To32[value];
else
return (char) value;
}
回答by trashgod
You can print the corresponding Unicode Control Pictures, e.g. \u2400for ? (nul).
您可以打印相应的Unicode 控制图片，例如\u2400用于 ? ( nul).
回答by pracheth
class prg1{
public static void main(char a){
int b=(int)a;
System.out.println("ASCII value ="+b);
}
}
回答by Akhil Ajay
Try this:
尝试这个：
public static void main(String[] args) {
String a = "a";
char b = a.charAt(0);
int c = b;
System.out.println(c);
}
