如何解决 Laravel 4 中的“目标 [接口] 不可实例化”?

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时间:2020-09-14 10:38:09  来源:igfitidea点击:

How do I solve "Target [Interface] is not instantiable" in Laravel 4?

phplaravellaravel-4inversion-of-controlioc-container

提问by noobmaster69

My error message:

我的错误信息:

Illuminate \ Container \ BindingResolutionException 
Target [Project\Backend\Service\Validation\ValidableInterface] is not instantiable.

I understand that interfaces and abstract classes are not instantiable so I know that Laravel should not be trying to instantiate my interface. Yet somehow it's trying to and I suspect this may be a binding issue...even though I believe I have bound it correctly and have registered it as a service provider.

我知道接口和抽象类是不可实例化的,所以我知道 Laravel 不应该尝试实例化我的接口。然而不知何故,它正在尝试并且我怀疑这可能是一个绑定问题......即使我相信我已经正确绑定它并将其注册为服务提供商。

I should mention that I have taken this example out of Chris Fidao's "Implementing Laravel" and it's almost identical!

我应该提一下,我从 Chris Fidao 的“实现 Laravel”中拿了这个例子,它几乎是一样的!

This is the first couple of lines of my form class:

这是我的表单类的前几行:

namespace Project\Backend\Service\Form\Job;

use Project\Backend\Service\Validation\ValidableInterface;
use Project\Backend\Repo\Job\JobInterface;

class JobForm {

    /**
     * Form Data
     *
     * @var array
     */
    protected $data;

    /**
     * Validator
     *
     * @var \Project\Backend\Form\Service\ValidableInterface
     */
    protected $validator;

    /**
     * Job repository
     *
     * @var \Project\Backend\Repo\Job\JobInterface
     */
    protected $job;

    public function __construct(ValidableInterface $validator, JobInterface $job)
    {
        $this->validator = $validator;
        $this->job = $job;
    }

This is the first few lines of my validator class:

这是我的验证器类的前几行:

namespace Project\Backend\Service\Form\Job;

use Project\Backend\Service\Validation\AbstractLaravelValidator;

class JobFormValidator extends AbstractLaravelValidator {

    // Includes some validation rules

This is the abstract validator:

这是抽象验证器:

namespace Project\Backend\Service\Validation;

use Illuminate\Validation\Factory;

abstract class AbstractLaravelValidator implements ValidableInterface {

    /**
     * Validator
     *
     * @var \Illuminate\Validation\Factory
     */
    protected $validator;

    /**
     * Validation data key => value array
     *
     * @var Array
     */
    protected $data = array();

    /**
     * Validation errors
     *
     * @var Array
     */
    protected $errors = array();

    /**
     * Validation rules
     *
     * @var Array
     */
    protected $rules = array();

    /**
     * Custom validation messages
     *
     * @var Array
     */
    protected $messages = array();

    public function __construct(Factory $validator)
    {
        $this->validator = $validator;
    }

This is the code where I bind it all to the app:

这是我将其全部绑定到应用程序的代码:

namespace Project\Backend\Service\Validation;

use Illuminate\Support\ServiceProvider;
use Project\Backend\Service\Form\Job\JobFormValidator;

class ValidationServiceProvider extends ServiceProvider {

    public function register()
    {
        $app = $this->app;

        $app->bind('Project\Backend\Service\Form\Job\JobFormValidator', function($app)
        {
            return new JobFormValidator($app['validator']);
        });
    }
}

This is then registered in app/config/app.php:

然后在 app/config/app.php 中注册:

.....
'Project\Backend\Service\Validation\ValidationServiceProvider',
....

Finally these are the first few lines of my controller:

最后这些是我的控制器的前几行:

use Project\Backend\Repo\Job\JobInterface;
use Project\Backend\Service\Form\Job\JobForm;

class JobController extends \BaseController {

    protected $jobform;

    function __construct(JobInterface $job, JobForm $jobform)
    {
        $this->job = $job;
        $this->jobform = $jobform;
    }

回答by lukasgeiter

You need to tell Laravel which instance it should use for a certain interface when injecting it into the constructor via type hinting.

当通过类型提示将它注入构造函数时,你需要告诉 Laravel 它应该为某个接口使用哪个实例。

You do this using the bind()method (in your service provider for example)

您使用该bind()方法执行此操作(例如在您的服务提供商中)

$app->bind('JobInterface', 'Job'); // Job being the class you want to be used

I highly recommend you watch the video herewhere Taylor Otwell, the creator of Laravel, explains this and some other things.

我强烈建议你在这里观看Laravel 的创造者 Taylor Otwell 解释这个和其他一些事情的视频。

回答by Virat Gaywala - CSM

First you need to bind using

首先你需要使用绑定

/app/Providers/AppServiceProvider.php

/app/Providers/AppServiceProvider.php

<?php namespace App\Providers;

use Illuminate\Support\ServiceProvider;

class AppServiceProvider extends ServiceProvider {

    /**
     * Bootstrap any application services.
     *
     * @return void
     */
    public function boot()
    {
        //
    }

    /**
     * Register any application services.
     *
     * @return void
     */
    public function register()
    {
        //
        $this->app->bind('JobInterface', 'Job');

    }

}

Once you complete this change

完成此更改后

Run composer update

运行作曲家更新