Scala 检查字符串是否不包含特殊字符
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Scala check if string contains no special chars
提问by MeiSign
I have written the following code to check whether a string contains special chars or not. The code looks too complicated to me but I have no idea how to make it simpler. Any Ideas?
我编写了以下代码来检查字符串是否包含特殊字符。代码对我来说看起来太复杂了，但我不知道如何使它更简单。有任何想法吗？
def containsNoSpecialChars(string: String): Boolean = {
val pattern = "^[a-zA-Z0-9]*$".r
return pattern.findAllIn(string).mkString.length == string.length
} //> containsNoSpecialChars: (string: String)Boolean
containsNoSpecialChars("bl!a ") //> res0: Boolean = false
containsNoSpecialChars("bla9") //> res1: Boolean = true
回答by Ion Cojocaru
This uses the Java string:
这使用 Java 字符串：
word.matches("^[a-zA-Z0-9]*$")
or if you do not want to deal with Regex one can benefit from Scala's RichString by using either:
或者，如果您不想处理 Regex，则可以使用以下任一方法从 Scala 的 RichString 中受益：
word.forall(_.isLetterOrDigit)
or:
或者：
!word.exists(!_.isLetterOrDigit)
回答by Mark Lister
scala> val ordinary=(('a' to 'z') ++ ('A' to 'Z') ++ ('0' to '9')).toSet
ordinary: scala.collection.immutable.Set[Char] = Set(E, e, X, s, x, 8, 4, n, 9, N, j, y, T, Y, t, J, u, U, f, F, A, a, 5, m, M, I, i, v, G, 6, 1, V, q, Q, L, b, g, B, l, P, p, 0, 2, C, H, c, W, h, 7, r, K, w, R, 3, k, O, D, Z, o, z, S, d)
scala> def isOrdinary(s:String)=s.forall(ordinary.contains(_))
isOrdinary: (s: String)Boolean
scala> isOrdinary("abc")
res4: Boolean = true
scala> isOrdinary("abc!")
res5: Boolean = false
I used a Set, the correct choice logically, but it should also work with a Vector which will avoid you looking at the jumbled letters...
我使用了 Set，这是逻辑上正确的选择，但它也应该与 Vector 一起使用，这样可以避免您看到混乱的字母...
回答by Ashalynd
def containsNoSpecialChars(string: String) = string.matches("^[a-zA-Z0-9]*$")
