php CodeIgniter $this->input->get() 不工作
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/14046884/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
CodeIgniter $this->input->get() not working
提问by KraigBalla
I'm not sure why this is not working. I have allow_get_array = TRUE in the config file. Here's what I am trying to do..
我不确定为什么这不起作用。我在配置文件中有 allow_get_array = TRUE 。这就是我想要做的..
This is the link that the user will click from their email
这是用户将从他们的电子邮件中点击的链接
http://www.site.com/confirm?code=f8c53b1578f7c05471d087f18b343af0c3a638
confirm.php Controller:
confirm.php 控制器：
$code = $this->input->get('code');
also tried
也试过
$code = $this->input->get('code', TRUE);
Any ideas?
有任何想法吗？
采纳答案by KraigBalla
I did this and it worked without having to change the config file:
我这样做了，它无需更改配置文件即可工作：
//put some vars back into $_GET.
parse_str(substr(strrchr($_SERVER['REQUEST_URI'], "?"), 1), $_GET);
// grab values as you would from an ordinary $_GET superglobal array associative index.
$code = $_GET['code'];
回答by PhearOfRayne
In your config.phpchange the following:
在您的config.php更改中：
$config['uri_protocol'] = 'AUTO';
$config['permitted_uri_chars'] = 'a-z 0-9~%.:_\-';
$config['enable_query_strings'] = FALSE;
To:
到：
$config['uri_protocol'] = 'REQUEST_URI';
$config['permitted_uri_chars'] = 'a-z 0-9~%.:_\-?';
$config['enable_query_strings'] = TRUE;
Instead of messing with Query Strings you could change your URI to use segments like http://www.site.com/confirm/code/f8c53b1578f7c05471d087f18b343af0c3a638. To access the code segment you would use $this->uri->segment(3);. Personally I prefer this way as to using Query Strings. See URI Class
您可以更改 URI 以使用像http://www.site.com/confirm/code/f8c53b1578f7c05471d087f18b343af0c3a638. 要访问代码段，您将使用$this->uri->segment(3);. 我个人更喜欢这种方式来使用查询字符串。请参阅URI 类
回答by Silvio Delgado
Use this:
用这个：
$code = isset($_REQUEST['code']) ? $_REQUEST['code'] : NULL;
EDIT:
编辑：
In PHP >=7.0, you can do this:
在 PHP >=7.0 中，你可以这样做：
$code = $_REQUEST['code'] ?? NULL;
回答by itsme
can you please try
你能试试吗
http://www.site.com/confirm/?code=f8c53b1578f7c05471d087f18b343af0c3a638
instead of
代替
http://www.site.com/confirm?code=f8c53b1578f7c05471d087f18b343af0c3a638
without any config or else edit please
没有任何配置，否则请编辑
