访问 char c++ 中的单个位
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Access individual bits in a char c++
提问by AnotherProgrammer
How would i go about accessing the individual bits inside a c++ type, charor any c++ other type for example.
例如，我将如何访问 C++ 类型char或任何 C++ 其他类型中的各个位 。
回答by Matt
If you want access bit N:
如果你想访问位N：
Get: (INPUT >> N) & 1;
得到： (INPUT >> N) & 1;
Set: INPUT |= 1 << N;
放： INPUT |= 1 << N;
Unset: INPUT &= ~(1 << N);
取消设置： INPUT &= ~(1 << N);
Toggle: INPUT ^= 1 << N;
切换： INPUT ^= 1 << N;
回答by qdii
You would use the binary operators |(or), &(and) and ^(xor) to set them. To set the third bit of variable a, you would type, for instance:?
您可以使用二元运算符|(or)、&(and) 和^(xor) 来设置它们。要设置 variable 的第三位a，您可以输入，例如：?
a = a | 0x4
// c++ 14
a = a | 0b0100
Note that 4's binary representation is 0100
注意 4 的二进制表示是 0100
回答by brut3f0rc3
That is very easy Lets say you need to access individual bits of an integer Create a mask like this int mask =1; now, anding your numberwith this mask gives the value set at the zeroth bit in order to access the bit set at ith position (indexes start from zero) , just and with (mask<
这很容易 假设您需要访问整数的各个位 创建一个像这样的掩码 int mask =1; 现在，将您的数字与此掩码一起给出设置在第零位的值，以便访问在第 i 个位置设置的位（索引从零开始），只需并使用 (mask<
