Java Selenium 驱动程序 - 在列表中选择所需的 li 项
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Selenium driver - select the desired li item in the list
提问by TimeIsNear
In a list of 8 Elements I would select the one that contains the search text in children div. I need this because the elements of the list changes order every time. Here I would like to select the one that contains the text "TITLE TO LISTEN". How do I scroll through the list and select the wish li?
在 8 个元素的列表中，我将选择包含子 div 中搜索文本的元素。我需要这个，因为列表的元素每次都会改变顺序。在这里，我想选择包含文本“TITLE TO LISTEN”的那个。如何滚动列表并选择愿望 li？
Thanks in advance
提前致谢
Here one li:
这里一里：
...
<li id="3636863298979137009" class="clearfix" data-size="1" data-fixed="1" data-side="r">
<div class="userContentWrapper">
<div class="jki">
<span class="userContent">
TITLE TO LISTEN
</div>
<div class="TimelineUFI uiContainer">
<form id="u_0_b0" class="able_item collapsed_s autoexpand_mode" onsubmit="return window.Event && E" action="/ajax/ufi/modify.php" method="post" >
<input type="hidden" value="1" name="data_only_response" autocomplete="off">
<div class="TimelineFeedbackHeader">
<a class="ction_link" role="button" title="Journal" data-ft="{"tn":"J","type":25}" rel="dialog" href="/ajax/" tabindex="0" rip-style-bordercolor-backup="" style="" rip-style-borderstyle-backup="" >LISTEN</a>
</div>
</form>
</div>
</div>
</li>
</ol>
</div>
...
I tried this code, but it don't work because the elements ids change each time.
我试过这段代码，但它不起作用，因为元素 id 每次都会改变。
driver.findElement(By.xpath("//li[8]/div[2]/div/div[2]/form/div/div/span[2]/a")).click();
For example:
例如：
If text contain "TEXT TO LISTEN": li[3]/div[2]/div/div/div[2]/div/div/span
Link "listen" i want to click : li[3]/div[2]/div/div[2]/form/div/div/span[2]/a
here is number 3, but the order may change. I would first like to get that number and then click on the right link
这是第 3 条，但顺序可能会改变。我想先得到那个号码，然后点击右边的链接
采纳答案by Nat
You could get list of all li elements, and then search for specified text
您可以获得所有 li 元素的列表，然后搜索指定的文本
for(int i=0; i< listOfLiElements.Count, i++){
if(listOfLiElements[i].FindElement(By.ClassName("userContent")).Text == "TITLE TO LISTEN")
{
correctElement = listOfLiElements[i].FindElement(By.TagName("a"));
i =listOfLiElements.Count;
}
}
回答by Petr Mensik
Well, then just iterate through for each and ask if the current element has the right text inside it.
好吧，然后只需遍历每个元素并询问当前元素是否包含正确的文本。
List<Element> listOfLiTags = driver.findElement(By.Id("yourUlId")).findElements(By.TagName("li"));
for(Element li : listOfLiTags) {
String text = li.getElement(By.ClassName("userContent").getText();
if(text.equals("TITLE TO LISTEN") {
//do whatever you want and don't forget break
break;
}
}
Note that this is much more easier with CssSelector API.
请注意，使用CssSelector API会更容易。
List<Element> listOfSpans = driver.findElements(
By.CssSelector("ul[id=yourId] li span[class=userContent]");
Now just iterate and ask for the right text:)
现在只需迭代并要求正确的文本:)
回答by Sandeep Choudhary
Use this
用这个
driver.findElement(By.xpath("//li[contains(text(), 'Your text goes here')]"))
EDIT: just realised it's very old ques and you might have got ans by now, so for others who are looking for answer to this question.
编辑：刚刚意识到这是一个非常古老的问题，你现在可能已经得到了答案，所以对于正在寻找这个问题答案的其他人。
回答by Praveen
You can try this :
你可以试试这个：
public void ClickLink()
{
WebElement ol =driver.findElement(By.id("ol"));
List<WebElement> lis=ol.findElements(By.tagName("li"));
ArrayList<String> listFromGUI=new ArrayList<>();
for(int i=0;i<lis.size();i++)
{
WebElement li=ol.findElement(By.xpath("//ol[@id='ol']/li["+(i+1)+"]/div[2]/div/div/div[2]/div/div/span"));
if(li.getText().trim().equals("TEXT TO LISTEN"))
{
WebElement link=ol.findElement(By.xpath("//ol[@id='ol']/li["+(i+1)+"]/div[2]/div/div[2]/form/div/div/span[2]/a"));
if(link.getText().trim().equals("LISTEN"))
{
link.click();
break;
}
}
}
}
