Javascript Chrome“脚本可能只关闭由它打开的窗口”错误
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Chrome “Scripts may close only the windows that were opened by it” error
提问by Keefe
window.close();//false
window.open(location, '_self', '');
window.close();//false
open(location, '_self').close();//false
Chrome 45.0.2454.85 m, Firefox also has the problem.
Chrome 45.0.2454.85 m，Firefox 也有问题。
Please help...
请帮忙...
回答by Roboroads
You should store your opened window in a variable.
您应该将打开的窗口存储在变量中。
var popup = window.open(location, '_blank', '');
popup.close();
EDIT: Opening in _self does not work since you open a new page in the same screen, you might want to do _blank like i've edited.
编辑：在 _self 中打开不起作用，因为您在同一屏幕中打开了一个新页面，您可能想要像我编辑过的那样做 _blank。
