Linux：删除多个文件的文件扩展名
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4509485/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Linux: remove file extensions for multiple files
提问by rp101
I have many files with .txt extension. How to remove .txt extension for multiple files in linux?
我有很多扩展名为 .txt 的文件。如何在 linux 中删除多个文件的 .txt 扩展名？
I found that
我找到
rename .old .new *.old
substitutes .oldextension to the .new
替代.old扩展到.new
Also I want to do this for files in sub-folders.
我也想对子文件夹中的文件执行此操作。
采纳答案by thkala
renameis slightly dangerous, since according to its manual page:
rename有点危险，因为根据其手册页：
rename will rename the specified files by replacing the firstoccurrence of...
重命名将通过替换第一次出现的...来重命名指定的文件
It will happily do the wrong thing with filenames like c.txt.parser.y.
它会很高兴地对像c.txt.parser.y.
Here's a solution using findand bash:
这是使用findand的解决方案bash：
find -type f -name '*.txt' | while read f; do mv "$f" "${f%.txt}"; done
Keep in mind that this will break if a filename contains a newline (rare, but not impossible).
请记住，如果文件名包含换行符（很少见，但并非不可能），这将中断。
If you have GNU find, this is a more solid solution:
如果您找到 GNU，这是一个更可靠的解决方案：
find -type f -name '*.txt' -print0 | while read -d $'for i in `find myfolder -type d`; do
rename .old .new $i/*.old
done
' f; do mv "$f" "${f%.txt}"; done
回答by robert
You can explicitly pass in an empty string as an argument.
您可以显式传入一个空字符串作为参数。
rename .old '' *.old
rename .old '' *.old
And with subfolders, find . -type d -exec rename .old '' {}/*.old \;. {}is the substitute for the entry found with find, and \;terminates the arglist for the command given after -exec.
对于子文件夹，find . -type d -exec rename .old '' {}/*.old \;. {}是用 找到的条目的替代find，并\;终止在 之后给出的命令的 arglist -exec。
回答by Konrad Garus
For subfolders:
对于子文件夹：
find ./ -name "*.old" -exec sh -c 'mv rename 's/\.txt$//' *.txt
`basename "for file in *.old
touch (basename "$file" .old).new
end
" .old`.new' '{}' \;
回答by Chris Cowan
I use this:
我用这个：
for f in ./**/*.old; do
mv "${f}" "${f%.old}"
done
回答by Andrew S
The Perl version of rename can remove an extension as follows:
Perl 版本的 rename 可以删除扩展名，如下所示：
function chgext () {
local srcext=".old"
local dstext=""
local dir="."
[[ "$#" -ge 1 ]] && srcext=""
[[ "$#" -gt 2 ]] && dstext="" dir="" || dir="${2:-.}"
local bname=''
for f in "${dir}"/**/*"${srcext}"; do
bname="${f%${srcext}}"
echo "${bname}{${srcext} → ${dstext}}"
mv "${f}" "${bname}${dstext}"
done
}
This could be combined with find in order to also do sub-folders.
这可以与 find 结合使用，以便也做子文件夹。
回答by Bruno Alano
In Fish, you can do
在鱼中，你可以做
chgext
chgext src
chgext src dir
chgext src dst dir
Where `src` is the extension to find (default: ".old")
`dst` is the extension to replace with (default: "")
`dir` is the directory to act on (default: ".")
回答by svvac
In case it helps, here's how I do it with zsh:
如果有帮助，以下是我使用 zsh 的方法：
for i in *;do mv ${i} ${i/%.pdf/} ;done
The ${x%pattern}construct in zsh removes the shortest occurence of patternat the end of $x. Here it is abstracted as a function:
将${x%pattern}在zsh的结构去除的最短occurencepattern在年底$x。这里抽象为一个函数：
Usage:
用法：
##代码##回答by shahin aref
execute in bash linux
在 bash linux 中执行
##代码##