ios 在 Swift 中保存 CoreData 对多关系

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时间:2020-08-31 01:42:21  来源:igfitidea点击:

Saving CoreData to-many relationships in Swift

iosmacoscore-dataswiftrelationship

提问by Pirijan

I have a one-to-many relationship that looks like so,

我有一个一对多的关系,看起来像这样,

coredata model

核心数据模型

I've set up my model classes in a file to match:

我已经在文件中设置了我的模型类以匹配:

import CoreData
import Foundation

class Board: NSManagedObject {
    @NSManaged var boardColor: String
    @NSManaged var boardCustomBackground: AnyObject?
    @NSManaged var boardID: String
    @NSManaged var boardName: String
    @NSManaged var lists: NSSet
}

class List: NSManagedObject {
    @NSManaged var listID: String
    @NSManaged var listName: String
    @NSManaged var board: Board
}

Because I'm fetching data from multiple JSON endpoints, I have to save my lists seperately from my boards. What I want to do is create/update a list for a board with a matching boardID.

因为我从多个 JSON 端点获取数据,所以我必须将我的列表与我的板分开保存。我想要做的是为具有匹配 boardID 的板创建/更新列表

Here's where I am after multiple attempts:

这是我多次尝试后的位置:

func saveList(boardID: String, listName: String, listID: String) {
    let request = NSFetchRequest(entityName: "Board")
    var error: NSError? = nil
    request.predicate = NSPredicate(format: "boardID like %@", boardID)
    let results: NSArray = context.executeFetchRequest(request, error: &error)
    if results.count > 0 {
        for result in results {
            let board = result as Board
            let list = NSEntityDescription.insertNewObjectForEntityForName("List", inManagedObjectContext: context) as List
            println(" want to save \(listName) in \(board.boardName)")
            board.lists.addListObject(lists)
            list.listName = listName
            list.listID = listID
        }
    }
}

Based on Defining CoreData Relationships in Swiftand this, I tried to implement @Keenle's answer for define list objects inside a board:

基于在 Swiftthis 中定义 CoreData 关系,我尝试实现@Keenle 的答案,用于在板内定义列表对象:

import Foundation

extension Board {
    func addListObject(value:List) {
        var items = self.mutableSetValueForKey("lists");
        items.addObject(value)
    }

    func removeListObject(value:List) {
        var items = self.mutableSetValueForKey("lists");
        items.removeObject(value)
    }
}

However, I ran into the following error at board.lists.addListObject(lists): 'NSSet' does not have a member named 'addListObject'`

但是,我在以下位置遇到了以下错误board.lists.addListObject(lists)“NSSet”没有名为“addListObject”的成员

Instead of board.lists.addListObject(lists), I also tried board.lists.listName = listNameas implied in this Obj-C example, but that sadly didn't work either.

取而代之的是board.lists.addListObject(lists),我也board.lists.listName = listName按照这个Obj-C 示例中的暗示进行了尝试,但遗憾的是,这也不起作用。

(Also, The printlnoutput is correctly specifying the right board and list.)

(此外,println输出正确指定了正确的板和列表。)

Thanks in advance!

提前致谢!

回答by Martin R

In a one-to-many relationship, it is easier to set the "to-one" direction of the inverse relationships, in your case just

在一对多关系中,设置反向关系的“一对一”方向更容易,在您的情况下

list.board = board

so that the extension methods are actually not needed here.

所以这里实际上不需要扩展方法。

回答by Keenle

You should invoke addListObject(...)on boardobject:

您应该addListObject(...)board对象上调用:

board.addListObject(list) // notice that we pass just one object

Additionaly, if you want to be able to add a set of lists to particular boardobject, you can enhance you Boardclass extension with methods that accept set of objects:

此外,如果您希望能够向特定board对象添加一组列表,您可以Board使用接受一组对象的方法来增强类扩展:

func addList(values: NSSet) {
    var items = self.mutableSetValueForKey("lists");
    for value in values {
        items.addObject(value)
    }
}

func removeList(values: NSSet) {
    var items = self.mutableSetValueForKey("lists");
    for value in values {
        items.removeObject(value)
    }
}

回答by FranMowinckel

If you define:

如果你定义:

@NSManaged var lists: Set<List>

Then you can do:

然后你可以这样做:

board.lists.insert(list)