从 PHP 中的 JSON POST 读取 HTTP 请求正文的问题
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Issue reading HTTP request body from a JSON POST in PHP
提问by Hartley Brody
I'm writing a script that is registered as an endpoint for a webhook. I know that it's successfully registered because I'm writing the header of every request to my server logs. Here's a sample:
我正在编写一个注册为 webhook 端点的脚本。我知道它已成功注册，因为我正在将每个请求的标头写入服务器日志。这是一个示例：
Content-Type: text/xml; charset=UTF-8
User-Agent: Jakarta Commons-HttpClient/3.1
Host: =={obfuscated}==
Content-Length: 1918
The API that I've registered with is POST-ing a JSON object to my script, and I'd like to parse that object using PHP. As you can see from the request header, there's a nice big fat JSON object waiting to be parsed. It seems straightforward, but it hasn't been.
我注册的 API 是将 JSON 对象 POST 到我的脚本中，我想使用 PHP 解析该对象。正如您从请求标头中看到的，有一个很大的 JSON 对象等待解析。看起来很简单，但事实并非如此。
At first I tried using $_POST['json']or just $_POSTbut since the data isn't in an array, I wasn't really sure how to access it like that.
起初我尝试使用$_POST['json']or just$_POST但由于数据不在数组中，我不确定如何像那样访问它。
I've tried using file_get_contents('php://input')and fopen('php://input', 'r')with and without json_decode()but no luck. I can't use http_get_request_body()since the server I'm on doesn't have PECL and that's out of my control.
我试过使用file_get_contents('php://input')和fopen('php://input', 'r')不使用，json_decode()但没有运气。我无法使用，http_get_request_body()因为我所在的服务器没有 PECL，这是我无法控制的。
Are there any other ways to interact with the POST-ed JSON object that I'm missing? Thanks!
还有其他方法可以与我缺少的 POST-ed JSON 对象进行交互吗？谢谢！
回答by Hartley Brody
Thanks to others for the input. It turns out that I just needed
感谢其他人的投入。原来我只需要
$inputJSON = file_get_contents('php://input');
$input = json_decode($inputJSON, TRUE); //convert JSON into array
where the second parameter in json_decodereturned the object as an array.
其中第二个参数以json_decode数组形式返回对象。
Hope this helps someone else!
希望这对其他人有帮助！
回答by Exequiel Aguirre
Even when the following works.
即使以下有效。
$inputJSON = file_get_contents('php://input');
If you want to continue using $_POST send the data as FormData
如果您想继续使用 $_POST 将数据作为 FormData 发送
var fd = new FormData();
fd.append('key', 'value');
return axios.post('url', fd)
