我如何解决线程“main”中的异常 java.lang.NoSuchMethodError: main
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How can i resolve the Exception in thread "main" java.lang.NoSuchMethodError: main
提问by user2592584
I have this code. Eclipse tells me that the syntax is correct but when I run the program it gives me this error:
我有这个代码。Eclipse 告诉我语法是正确的，但是当我运行程序时，它给了我这个错误：
Exception in thread "main" java.lang.NoSuchMethodError: main
线程“main”中的异常 java.lang.NoSuchMethodError: main
What's wrong?
怎么了？
import java.awt.Color;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
public class Main extends JFrame {
private static final long serialVersionUID = 1L;
public void main(String[] args){
JFrame Main = new JFrame("TEST");
Main.setSize(600, 600);
Main.setLocationRelativeTo(null);
Main.setVisible(true);
Main.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
//Adding JPanel
JPanel panel = new JPanel();
Main.add(panel);
//JPanel settings
panel.setLayout(null);
panel.setBackground(Color.GREEN);
//Adding JButton
JButton button = new JButton("Button 1");
JButton button2 = new JButton("Button2");
panel.add(button);
panel.add(button2);
//Button action
button.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e) {
JPanel panel = new JPanel();
JPanel panel2 = new JPanel();
Main.this.getContentPane().remove(panel);
Main.this.getContentPane().add(panel2);
Main.this.getContentPane().validate();
}
});
//JButton settings
button.setBounds(70, 160, 200, 200);
button2.setBounds(320, 160, 200, 200);
}
}
回答by sanbhat
Your main method is notstatic, and you should make it static. Check thisto see why
您的主要方法不是static，您应该使用它static。检查这个看看为什么
public static void main(String [] args)
回答by Suresh Atta
Your main method should be static
你的主要方法应该是 static
public static void main(String[] args){
----
}
And see why ??Why is the Java main method static?
看看为什么？为什么 Java 的 main 方法是静态的？
回答by Andrew Thompson
The class requires a method with a signature of:
该类需要一个具有以下签名的方法：
public static void main(String[])
回答by Svend Hansen
You have to make your main method static:
你必须使你的主要方法静态：
public static void main(String[] args) {
}
回答by newuser
public static void main(String[] args)
instead of
代替
public void main(String[] args)
publicmeans that the method is visible and can be called from other objects of other types. Other alternatives are private, protected, package and package-private. See here for more details.
public意味着该方法是可见的，可以从其他类型的其他对象调用。其他替代方案是私有的、受保护的、包和包私有的。请参阅此处了解更多详情。
staticmeans that the method is associated with the class, not a specific instance (object) of that class. This means that you can call a static method without creating an object of the class.
static意味着该方法与类相关联，而不是该类的特定实例（对象）。这意味着您可以在不创建类的对象的情况下调用静态方法。
voidmeans that the method has no return value. If the method returned an int you would write int instead of void.
void意味着该方法没有返回值。如果该方法返回一个 int，您将编写 int 而不是 void。
The combination of all three of these is most commonly seen on the main method which most tutorials will include.
所有这三个的组合在大多数教程将包含的主要方法中最常见。
回答by gyorgyabraham
Your main method must be static (ie. class-bound not instance-bound) because at the time of starting your app there no class instances that could call your class' main method.
您的 main 方法必须是静态的（即类绑定而不是实例绑定），因为在启动应用程序时，没有可以调用类的 main 方法的类实例。
回答by Manish Doshi
The class requires a method with a signature of like this:
该类需要一个具有如下签名的方法：
public static void main(String[])
