Python：如何不断重复程序直到获得特定输入？
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Python: How to keep repeating a program until a specific input is obtained?
提问by user3033494
I have a function that evaluates input, and I need to keep asking for their input and evaluating it until they enter a blank line. How can I set that up?
我有一个评估输入的函数，我需要不断询问他们的输入并评估它，直到他们输入一个空行。我该如何设置？
while input != '':
evaluate input
I thought of using something like that, but it didn't exactly work. Any help?
我想使用类似的东西，但它并没有完全奏效。有什么帮助吗？
采纳答案by user3033494
There are two ways to do this. First is like this:
有两种方法可以做到这一点。首先是这样的：
while True: # Loop continuously
inp = raw_input() # Get the input
if inp == "": # If it is a blank line...
break # ...break the loop
The second is like this:
第二个是这样的：
inp = raw_input() # Get the input
while inp != "": # Loop until it is a blank line
inp = raw_input() # Get the input again
Note that if you are on Python 3.x, you will need to replace raw_inputwith input.
请注意，如果您使用的是 Python 3.x，则需要替换raw_input为input.
回答by theodox
you probably want to use a separate value that tracks if the input is valid:
您可能想要使用一个单独的值来跟踪输入是否有效：
good_input = None
while not good_input:
user_input = raw_input("enter the right letter : ")
if user_input in list_of_good_values:
good_input = user_input
回答by Shahid Ghafoor
This is a small program that will keep asking an input until required input is given.
这是一个小程序，它将不断询问输入，直到给出所需的输入。
required_number = 18
while True:
number = input("Enter the number\n")
if number == required_number:
print "GOT IT"
else:
print ("Wrong number try again")回答by Adriano Araujo Valumin
Easier way:
更简单的方法：
#required_number = 18
required_number=input("Insert a number: ")
while required_number != 18
print("Oops! Something is wrong")
required_number=input("Try again: ")
if required_number == '18'
print("That's right!")
#continue the code
