php 警告：不能使用标量值作为数组
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Warning: Cannot use a scalar value as an array in
提问by Julian Martinez
I am seeing the following error when executing my status script:
我在执行我的状态脚本时看到以下错误：
Warning: Cannot use a scalar value as an array in
$result[$array[$i*2]] = $array[$i*2+1];
What am I doing wrong? I have included the full code below:
我究竟做错了什么？我在下面包含了完整的代码：
<?php
// Set the host and port
$host = "ip_goes_here";
$port = port_goes_here;
// Open the socket connection to the server
$fp = fsockopen("udp://".$host, $port);
// Set the string to send to the server
$string = "\xff\xff\xff\xffgetinfo";
// Set the socket timeout to 2 seconds
socket_set_timeout($fp, 2);
// Actually send the string
fwrite($fp, $string);
// Read the first 18 bytes to get rid of the header and do the error checking here
if(!fread($fp, 18)) {
die("Oh God, the pain!");
}
// Get the status of the socket, to be used for the length left
$status = socket_get_status($fp);
// Read the rest
$info = fread($fp, $status['unread_bytes']);
// Explode the result of the fread into another variable
$array = explode("\", $info);
// Loop through and create a result array, with the key being even, the result, odd
for($i = 0; $i < count($array)/2; $i++) {
$result[$array[$i*2]] = $array[$i*2+1];
}
// Print the result for error checking
print_r($result);
// Close the file pointer
fclose($fp);
The line I mentioned is causing the errors. I have no idea what I am doing wrong here...
我提到的那条线导致了错误。我不知道我在这里做错了什么......
回答by Havelock
You can try declaring the variable $result, as an array, before using it.
您可以尝试$result在使用之前将变量声明为数组。
$result = array();
// Loop through and create a result array, with the key being even, the result, odd
for($i = 0; $i < count($array)/2; $i++) {
$result[$array[$i*2]] = $array[$i*2+1];
}
回答by Davidson Campos
xdebug archive in session path c:\xammp\temp\xdebug___.txt with 2GB, delete and solve this, this work to me
会话路径 c:\xammp\temp\xdebug___.txt 中的 xdebug 存档，大小为 2GB，删除并解决此问题，这对我有用
