如何防止通过 PHP mail() 发送的邮件变成垃圾邮件？
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How do I prevent mails sent through PHP mail() from going to spam?
提问by Partyboy
I am using PHP's mail() function to send emails (sendmail process is running). But all the mails are going to spam (in case of gmail). I have tried many tricks that I found on the net but none is working, please tell me about any sure-shot trick.
我正在使用 PHP 的 mail() 函数发送电子邮件（sendmail 进程正在运行）。但是所有的邮件都会变成垃圾邮件（在 gmail 的情况下）。我尝试了很多我在网上找到的技巧，但都没有奏效，请告诉我任何可靠的技巧。
回答by
You must to add a needle headers:
您必须添加一个针头：
Sample code :
示例代码：
$headers = "From: [email protected]\r\n";
$headers .= "Reply-To: [email protected]\r\n";
$headers .= "Return-Path: [email protected]\r\n";
$headers .= "CC: [email protected]\r\n";
$headers .= "BCC: [email protected]\r\n";
if ( mail($to,$subject,$message,$headers) ) {
echo "The email has been sent!";
} else {
echo "The email has failed!";
}
?>
回答by Oswald
There is no sure shot trick. You need to explore the reasons why your mails are classified as spam. SpamAssassin hase a page describing Some Tips for Legitimate Senders to Avoid False Positives. See also Coding Horror: So You'd Like to Send Some Email (Through Code)
没有确定的投篮技巧。您需要探索您的邮件被归类为垃圾邮件的原因。SpamAssassin 有一个页面描述了合法发件人避免误报的一些技巧。另见编码恐怖：所以你想发送一些电子邮件（通过代码）
回答by Ahmed Medhat
<?php
$subject = "this is a subject";
$message = "testing a message";
$headers .= "Reply-To: The Sender <[email protected]>\r\n";
$headers .= "Return-Path: The Sender <[email protected]>\r\n";
$headers .= "From: The Sender <[email protected]>\r\n";
$headers .= "Organization: Sender Organization\r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/plain; charset=iso-8859-1\r\n";
$headers .= "X-Priority: 3\r\n";
$headers .= "X-Mailer: PHP". phpversion() ."\r\n" ;
mail("[email protected]", $subject, $message, $headers);
?>
回答by Rikesh
Try PHP Mailer library.
Or Send mail through SMTP filter it before sending it.
Also Try to give all details like FROM, return-path.
试试PHP Mailer 库。
或通过 SMTP 发送邮件在发送之前过滤它。
还尝试提供所有详细信息，例如FROM, return-path。
回答by Ipsita Rout
$fromMail = 'set your from mail';
$boundary = str_replace(" ", "", date('l jS \of F Y h i s A'));
$subjectMail = "New design submitted by " . $userDisplayName;
$contentHtml = '<div>Dear Admin<br /><br />The following design is submitted by '. $userName .'.<br /><br /><a href="'.$sdLink.'"><b>Click here</b></a> to check the design.</div>';
$contentHtml .= '<div><a href="'.$imageUrl.'"><img src="'.$imageUrl.'" width="250" height="95" border="0" alt="my picture"></a></div>';
$contentHtml .= '<div>Name : '.$name.'<br />Description : '. $description .'</div>';
$headersMail = '';
$headersMail .= 'From: ' . $fromMail . "\r\n" . 'Reply-To: ' . $fromMail . "\r\n";
$headersMail .= 'Return-Path: ' . $fromMail . "\r\n";
$headersMail .= 'MIME-Version: 1.0' . "\r\n";
$headersMail .= "Content-Type: multipart/alternative; boundary = \"" . $boundary . "\"\r\n\r\n";
$headersMail .= '--' . $boundary . "\r\n";
$headersMail .= 'Content-Type: text/html; charset=ISO-8859-1' . "\r\n";
$headersMail .= 'Content-Transfer-Encoding: base64' . "\r\n\r\n";
$headersMail .= rtrim(chunk_split(base64_encode($contentHtml)));
try {
if (mail($toMail, $subjectMail, "", $headersMail)) {
$status = 'success';
$msg = 'Mail sent successfully.';
} else {
$status = 'failed';
$msg = 'Unable to send mail.';
}
} catch(Exception $e) {
$msg = $e->getMessage();
}
This works fine for me.It includes mail with image and a link and works for all sorts of mail ids. The clue is to use all the header perfectly.
这对我来说很好用。它包括带有图像和链接的邮件，适用于各种邮件 ID。线索是完美地使用所有标题。
If you are testing it from localhost, then set the below before checking:
如果您是从 localhost 测试它，请在检查之前设置以下内容：
How to set mail send from localhost xampp:
如何设置从 localhost xampp 发送邮件：
comment everything in
D:/xampp/sendmail/sendmail.iniand mention the below under[sendmail]
smtp_server=smtp.gmail.com smtp_port=587 error_logfile=error.log debug_logfile=debug.log [email protected] auth_password=your-mail-password [email protected]
In
D:/xampp/php/php.inia. Under[mail function]
SMTP = smtp.gmail.com smtp_port = 587
评论所有内容
D:/xampp/sendmail/sendmail.ini并在下面提及以下内容[发邮件]
smtp_server=smtp.gmail.com smtp_port=587 error_logfile=error.log debug_logfile=debug.log [email protected] auth_password=your-mail-password [email protected]
在
D:/xampp/php/php.ini一个。在下面【邮件功能】
SMTP = smtp.gmail.com smtp_port = 587
b. set sendmail_from = [email protected]c. uncomment sendmail_path = "\"D:\xamp\sendmail\sendmail.exe\" -t"
Hence it should be look like below
湾 设置sendmail_from = [email protected]c。取消注释 sendmail_path = "\"D:\xamp\sendmail\sendmail.exe\" -t" 因此它应该如下所示
sendmail_path = "\"D:\xamp\sendmail\sendmail.exe\" -t"
d. comment sendmail_path="D:\xamp\mailtodisk\mailtodisk.exe" Hence it should be look like below
d. 评论 sendmail_path="D:\xamp\mailtodisk\mailtodisk.exe" 因此它应该如下所示
;sendmail_path="D:\xamp\mailtodisk\mailtodisk.exe"
e. mail.add_x_header=Off
e. mail.add_x_header=Off
回答by SAVe
<?php
$to1 = '[email protected]';
$subject = 'Tester subject';
// To send HTML mail, the Content-type header must be set
$headers .= "Reply-To: The Sender <[email protected]>\r\n";
$headers .= "Return-Path: The Sender <[email protected]>\r\n";
$headers .= "From: [email protected]" ."\r\n" .
$headers .= "Organization: Sender Organization\r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=utf-8\r\n";
$headers .= "X-Priority: 3\r\n";
$headers .= "X-Mailer: PHP". phpversion() ."\r\n" ;
?>
