php 如何使 number_format() 不四舍五入

How to make number_format() not to round numbers up

提问by Psyche

I have this number:

我有这个号码：

$double = '21.188624';

After using number_format($double, 2, ',', ' ')I get:

使用后number_format($double, 2, ',', ' ')我得到：

21,19

But what I want is:

但我想要的是：

21,18

Any ideea how can I make this work?

任何想法我怎样才能使这项工作？

Thank you.

谢谢你。

回答by Wrikken

number_formatwill always do that, your only solution is to feed it something different:

number_format将始终这样做，您唯一的解决方案是喂它不同的东西：

$number = intval(($number*100))/100;

Or:

或者：

$number = floor(($number*100))/100;

回答by ustmaestro

I know that this an old question, but it still actual :) .

我知道这是一个老问题，但它仍然是实际的 :) 。

How about this function?

这个功能怎么样？

function numberFormatPrecision($number, $precision = 2, $separator = '.')
{
    $numberParts = explode($separator, $number);
    $response = $numberParts[0];
    if(count($numberParts)>1){
        $response .= $separator;
        $response .= substr($numberParts[1], 0, $precision);
    }
    return $response;
}

Usage:

用法：

// numbers test
numberFormatPrecision(19, 2, '.'); // expected 19 return 19
numberFormatPrecision(19.1, 2, '.'); //expected 19.1 return 19.1
numberFormatPrecision(19.123456, 2, '.'); //expected 19.12 return 19.12

// negative numbers test
numberFormatPrecision(-19, 2, '.'); // expected -19 return -19
numberFormatPrecision(-19.1, 2, '.'); //expected -19.1 return -19.1
numberFormatPrecision(-19.123456, 2, '.'); //expected -19.12 return -19.12

// precision test
numberFormatPrecision(-19.123456, 4, '.'); //expected -19.1234 return -19.1234

// separator test
numberFormatPrecision('-19,123456', 3, ','); //expected -19,123 return -19,123  -- comma separator

回答by methodin

floor($double*100)/100

回答by T30

I use this function:

我使用这个功能：

function cutNum($num, $precision = 2) {
    return floor($num) . substr(str_replace(floor($num), '', $num), 0, $precision + 1);
}

Usage examples:

用法示例：

cutNum(5)          //returns 5 
cutNum(5.6789)     //returns 5.67 (default precision is two decimals)
cutNum(5.6789, 3)  //returns 5.678
cutNum(5.6789, 10) //returns 5.6789
cutNum(5.6789, 0)  //returns 5. (!don't use with zero as second argument: use floor instead!)

---

---

Explanation: here you have the samefunction, just more verbose to help understanding its behaviour:

说明：这里你有相同的功能，只是更详细地帮助理解它的行为：

function cutNum($num, $precision = 2) {
    $integerPart = floor($num);
    $decimalPart = str_replace($integerPart, '', $num);
    $trimmedDecimal = substr($decimalPart, 0, $precision + 1);
    return $integerPart . $trimmedDecimal;
}

回答by Etienne Martin

Use the PHP native function bcdiv.

使用 PHP 原生函数bcdiv。

function numberFormat($number, $decimals = 2, $sep = ".", $k = ","){
    $number = bcdiv($number, 1, $decimals); // Truncate decimals without rounding
    return number_format($number, $decimals, $sep, $k); // Format the number
}

See this answerfor more details.

有关更多详细信息，请参阅此答案。

回答by Derezzed

Function (only precision):

功能（仅精度）：

function numberPrecision($number, $decimals = 0)
{
    $negation = ($number < 0) ? (-1) : 1;
    $coefficient = pow(10, $decimals);
    return $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
}

Examples:

例子：

numberPrecision(2557.9999, 2);     // returns 2557.99
numberPrecision(2557.9999, 10);    // returns 2557.9999
numberPrecision(2557.9999, 0);     // returns 2557
numberPrecision(2557.9999, -2);    // returns 2500
numberPrecision(2557.9999, -10);   // returns 0
numberPrecision(-2557.9999, 2);    // returns -2557.99
numberPrecision(-2557.9999, 10);   // returns -2557.9999
numberPrecision(-2557.9999, 0);    // returns -2557
numberPrecision(-2557.9999, -2);   // returns -2500
numberPrecision(-2557.9999, -10);  // returns 0

Function (full functionality):

功能（全功能）：

function numberFormat($number, $decimals = 0, $decPoint = '.' , $thousandsSep = ',')
{
    $negation = ($number < 0) ? (-1) : 1;
    $coefficient = pow(10, $decimals);
    $number = $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
    return number_format($number, $decimals, $decPoint, $thousandsSep);
}

Examples:

例子：

numberFormat(2557.9999, 2, ',', ' ');     // returns 2 557,99
numberFormat(2557.9999, 10, ',', ' ');    // returns 2 557,9999000000
numberFormat(2557.9999, 0, ',', ' ');     // returns 2 557
numberFormat(2557.9999, -2, ',', ' ');    // returns 2 500
numberFormat(2557.9999, -10, ',', ' ');   // returns 0
numberFormat(-2557.9999, 2, ',', ' ');    // returns -2 557,99
numberFormat(-2557.9999, 10, ',', ' ');   // returns -2 557,9999000000
numberFormat(-2557.9999, 0, ',', ' ');    // returns -2 557
numberFormat(-2557.9999, -2, ',', ' ');   // returns -2 500
numberFormat(-2557.9999, -10, ',', ' ');  // returns 0

回答by Abhishek Sharma

 **Number without round**        

   $double = '21.188624';
   echo intval($double).'.'.substr(end(explode('.',$double)),0,2);

**Output** 21.18

回答by Bill Stephen

$double = '21.188624';

$teX = explode('.', $double);

if(isset($teX[1])){
    $de = substr($teX[1], 0, 2);
    $final = $teX[0].'.'.$de;
    $final = (float) $final;
}else{
    $final = $double;   
}

final will be 21.18

决赛将是 21.18

回答by litux

The faster way as exploding(building arrays) is to do it with string commands like this:

爆炸（构建数组）的更快方法是使用这样的字符串命令：

$number = ABC.EDFG;
$precision = substr($number, strpos($number, '.'), 3); // 3 because . plus 2 precision  
$new_number = substr($number, 0, strpos($number, '.')).$precision;

The result ist ABC.ED in this case because of 2 precision If you want more precision just change the 3 to 4 or X to have X-1 precision

在这种情况下，结果是 ABC.ED 因为 2 精度如果您想要更高的精度，只需将 3 更改为 4 或 X 以具有 X-1 精度

Cheers

干杯

回答by Asaf Maoz

$finalCommishParts = explode('.',$commission);
$commisshSuffix = (isset($finalCommishParts[1])?substr($finalCommishParts[1],0,2):'00');
$finalCommish = $finalCommishParts[0].'.'.$commisshSuffix;