Java 从控制器转发到静态 html 页面
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Forward to a static html page from Controller
提问by Alexey Buistov
My spring mvc application has one single ContentNegotiatingViewResolver that defines JsonView for rendering json resonses:
我的 spring mvc 应用程序有一个 ContentNegotiatingViewResolver，它定义了用于呈现 json 响应的 JsonView：
<mvc:annotation-driven/>
<context:component-scan base-package="world.domination.test"/>
<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
<property name="mediaTypes">
<map>
<entry key="json" value="application/json"/>
</map>
</property>
<property name="defaultViews">
<list>
<bean class="com.secondmarket.connector.springmvc.MappingHymansonJsonViewEx"/>
</list>
</property>
</bean>
The whole application sits on root url "myapp". Everything works as I need.
整个应用程序位于根网址“myapp”上。一切都按我的需要工作。
The first questionis: how to return a static html page when accessing a certain url? Say, when accessing Spring uri /myapp/test I would like to render an html page /TestStuff.html that resides in root webapp folder.
第一个问题是：访问某个url时如何返回一个静态的html页面？说，在访问 Spring uri /myapp/test 时，我想呈现一个位于根 webapp 文件夹中的 html 页面 /TestStuff.html。
I went ahead and wrote a simple controller:
我继续写了一个简单的控制器：
@Controller
@RequestMapping("test")
public class TestConnector {
@Autowired
private RestTemplate tpl;
@RequestMapping(method = RequestMethod.GET)
public String get() {
return "/TestStuff.html";
}
@RequestMapping(method = RequestMethod.POST)
public String post(@RequestParam("url") String url, @RequestParam("data") String data) {
return tpl.postForObject(url, data, String.class, new HashMap<String, Object>());
}
}
The get() method is supposed to tell Spring to render a TestStuff.html, but instead I get an error saying that the view with name "/TestStuff.html" is missing.
get() 方法应该告诉 Spring 呈现一个 TestStuff.html，但我收到一个错误，说缺少名称为“/TestStuff.html”的视图。
The second questionis how to avoid the necessity to put extension to the URL. In my example, when I use /myapp/testinstead of /myapp/test.htmlmy ContentNegotiatingViewResolver uses a json view that renders {} (empty curly braces)
在第二个问题是如何避免的必要性，把扩展到的URL。在我的示例中，当我使用/myapp/test而不是/myapp/test.html我的 ContentNegotiatingViewResolver 使用呈现 {}（空花括号）的 json 视图
Any pointers are highly appreciated.
任何指针都受到高度赞赏。
回答by DwB
Instead of returning "/TestStuff.html" from your controller, try returning "redirect:/TestStuff.html".
不要从控制器返回“/TestStuff.html”，而是尝试返回“redirect:/TestStuff.html”。
Another option is to create and register a view resolver for your static pages. Perhaps something like this:
另一种选择是为您的静态页面创建和注册视图解析器。也许是这样的：
<bean id="staticViewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="prefix" value="/WEB-INF/static/"/>
<property name="suffix" value=".html"/>
</bean>
回答by John Mikic
The best way to do this is to use InternalResourceViewResolver combined with mvc:view-controller tag (see appropriate Spring Reference Manual for details). Just include the following into your application context XML file (in this case your static file TestStuff.html will be located in /WEB-INF/static-pages directory):
最好的方法是将 InternalResourceViewResolver 与 mvc:view-controller 标签结合使用（有关详细信息，请参阅相应的 Spring 参考手册）。只需将以下内容包含到您的应用程序上下文 XML 文件中（在这种情况下，您的静态文件 TestStuff.html 将位于 /WEB-INF/static-pages 目录中）：
<bean>
<bean id="staticPagesViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/static-pages/"/>
<property name="suffix" value=".html"/>
</bean>
<mvc:view-controller path="/test" view-name="TestStuff"/>
回答by Bruce Edge
tutorialspoint has a good complete example of this: http://www.tutorialspoint.com/spring/spring_static_pages_example.htm
tutorialspoint 有一个很好的完整示例：http: //www.tutorialspoint.com/spring/spring_static_pages_example.htm
