在 PHP 中将数字转换为月份名称

Convert number to month name in PHP

提问by user2710234

I have this PHP code:

我有这个 PHP 代码：

$monthNum = sprintf("%02s", $result["month"]);
$monthName = date("F", strtotime($monthNum));

echo $monthName;

But it's returning Decemberrather than August.

但它正在返回December而不是August.

$result["month"]is equal to 8, so the sprintffunction is adding a 0to make it 08.

$result["month"]等于 8，因此sprintf函数添加 a0使其成为08。

回答by Amal Murali

The recommended way to do this:

推荐的方法：

Nowadays, you should really be using DateTime objects for any date/time math. This requires you to have a PHP version >= 5.2. As shown in Glavi?'s answer, you can use the following:

如今，您真的应该将 DateTime 对象用于任何日期/时间数学运算。这要求您的 PHP 版本 >= 5.2。如Glavi? 的回答所示，您可以使用以下内容：

$monthNum  = 3;
$dateObj   = DateTime::createFromFormat('!m', $monthNum);
$monthName = $dateObj->format('F'); // March

The !formatting characteris used to reset everything to the Unix epoch. The mformat character is the numeric representation of a month, with leading zeroes.

该!格式化字符用于重置一切的Unix纪元。该m格式字符是一月份的数字表示，用前导零。

Alternative solution:

替代解决方案：

If you're using an older PHP version and can't upgrade at the moment, you could this solution. The second parameter of date()function accepts a timestamp, and you could use mktime()to create one, like so:

如果您使用的是较旧的 PHP 版本并且目前无法升级，则可以使用此解决方案。date()函数的第二个参数接受一个时间戳，您可以使用它mktime()来创建一个，如下所示：

$monthNum  = 3;
$monthName = date('F', mktime(0, 0, 0, $monthNum, 10)); // March

If you want the 3-letter month name like Mar, change Fto M. The list of all available formatting options can be found in the PHP manual documentation.

如果您想要 3 个字母的月份名称Mar，请更改F为M。所有可用格式选项的列表可以在PHP 手册文档中找到。

回答by Glavi?

Just because everyone is using strtotime() and date() functions, I will show DateTimeexample:

只是因为每个人都在使用 strtotime() 和 date() 函数，我将展示DateTime示例：

$dt = DateTime::createFromFormat('!m', $result['month']);
echo $dt->format('F');

回答by mintedsky

Use mktime():

使用mktime()：

<?php
 $monthNum = 5;
 $monthName = date("F", mktime(0, 0, 0, $monthNum, 10));
 echo $monthName; // Output: May
?>

See the PHP manual : http://php.net/mktime

请参阅 PHP 手册：http: //php.net/mktime

回答by Greg

strtotimeexpects a standard date format, and passes back a timestamp.

strtotime需要标准日期格式，并传回时间戳。

You seem to be passing strtotimea single digit to output a date format from.

您似乎正在传递strtotime一个数字来输出日期格式。

You should be using mktimewhich takes the date elements as parameters.

您应该使用mktimewhich 将日期元素作为参数。

Your full code:

您的完整代码：

$monthNum = sprintf("%02s", $result["month"]);
$monthName = date("F", mktime(null, null, null, $monthNum));

echo $monthName;

However, the mktime function does not require a leading zero to the month number, so the first line is completely unnecessary, and $result["month"]can be passed straight into the function.

但是，mktime 函数不需要月份数字前导零，因此第一行完全不需要，$result["month"]可以直接传递到函数中。

This can then all be combined into a single line, echoing the date inline.

然后可以将所有这些组合成一行，与内联日期相呼应。

Your refactored code:

您重构的代码：

echo date("F", mktime(null, null, null, $result["month"], 1));

...

...

回答by Dereckson

To do the conversion in respect of the current locale, you can use the strftimefunction:

要根据当前语言环境进行转换，您可以使用以下strftime函数：

setlocale(LC_TIME, 'fr_FR.UTF-8');                                              
$monthName = strftime('%B', mktime(0, 0, 0, $monthNumber));

datedoesn't respect the locale, strftimedoes.

date不尊重语言环境，strftime确实如此。

回答by Trent Renshaw

If you just want an array of month names from the beginning of the year to the end e.g. to populate a drop-down select, I would just use the following;

如果您只想要从年初到年底的月份名称数组，例如填充下拉选择，我将只使用以下内容；

for ($i = 0; $i < 12; ++$i) {
  $months[$m] = $m = date("F", strtotime("January +$i months"));
}

回答by Nishad Up

There are many ways to print a month from the given number. Pick one suite for you.

有很多方法可以从给定的数字中打印一个月。为您挑选一间套房。

1. date() function along with parameter 'F'

1. date() 函数以及参数 'F'

Code example:

代码示例：

$month_num = 10;
echo date("F", mktime(0, 0, 0, $month_num, 10)); //output: October

2. By creating php date object using createFromFormat()

2. 通过使用 createFromFormat() 创建 php 日期对象

Code Example

代码示例

$dateObj   = DateTime::createFromFormat('!m', $monthNum);
echo "month name: ".$dateObj->format('F'); // Output: October

3. strtotime() function

3. strtotime() 函数

echo date("F", strtotime('00-'.$monthNum.'-01')); // Output: October

4. mktime() function

4. mktime() 函数

echo date("F", mktime(null, null, null, $monthNum)); // Output: October

5. By using jdmonthname()

5. 通过使用 jdmonthname()

$jd=gregoriantojd($monthNum,10,2019);
echo jdmonthname($jd,0); // Output: Oct

回答by zzapper

adapt as required

根据需要适应

$m='08';
$months = array (1=>'Jan',2=>'Feb',3=>'Mar',4=>'Apr',5=>'May',6=>'Jun',7=>'Jul',8=>'Aug',9=>'Sep',10=>'Oct',11=>'Nov',12=>'Dec');
echo $months[(int)$m];

回答by Bryan Itur

If you have the month number, you can first create a date from it with a default date of 1st and default year of current year, then extract the month name from the date created:

如果您有月份编号，则可以首先从中创建一个默认日期为 1st 和当前年份的默认年份的日期，然后从创建的日期中提取月份名称：

echo date("F", strtotime(date("Y") ."-". $i ."-01"))

This code assume you have your month number stored in $i

此代码假设您将月份编号存储在 $i 中

Hope this helps someone

希望这有助于某人

回答by Matthew Park

$monthNum = 5;
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10));

I found this on https://css-tricks.com/snippets/php/change-month-number-to-month-name/and it worked perfectly.

我在https://css-tricks.com/snippets/php/change-month-number-to-month-name/上找到了这个，它运行得很好。