Python PyTorch：如何将张量的形状作为 int 列表
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PyTorch: How to get the shape of a Tensor as a list of int
提问by patapouf_ai
In numpy, V.shapegives a tuple of ints of dimensions of V.
在 numpy 中，V.shape给出 V 维的整数元组。
In tensorflow V.get_shape().as_list()gives a list of integers of the dimensions of V.
在 tensorflow 中V.get_shape().as_list()给出了 V 维的整数列表。
In pytorch, V.size()gives a size object, but how do I convert it to ints?
在 pytorch 中，V.size()给出一个大小对象，但如何将其转换为整数？
回答by alvas
For PyTorch v1.0 and possibly above:
对于 PyTorch v1.0 和可能更高版本：
>>> import torch
>>> var = torch.tensor([[1,0], [0,1]])
# Using .size function, returns a torch.Size object.
>>> var.size()
torch.Size([2, 2])
>>> type(var.size())
<class 'torch.Size'>
# Similarly, using .shape
>>> var.shape
torch.Size([2, 2])
>>> type(var.shape)
<class 'torch.Size'>
You can cast any torch.Size object to a native Python list:
您可以将任何 torch.Size 对象转换为原生 Python 列表：
>>> list(var.size())
[2, 2]
>>> type(list(var.size()))
<class 'list'>
In PyTorch v0.3 and 0.4:
在 PyTorch v0.3 和 0.4 中：
Simply list(var.size()), e.g.:
简单地list(var.size())，例如：
>>> import torch
>>> from torch.autograd import Variable
>>> from torch import IntTensor
>>> var = Variable(IntTensor([[1,0],[0,1]]))
>>> var
Variable containing:
1 0
0 1
[torch.IntTensor of size 2x2]
>>> var.size()
torch.Size([2, 2])
>>> list(var.size())
[2, 2]
回答by kmario23
If you're a fan of NumPyish syntax, then there's tensor.shape.
如果您喜欢NumPyish 语法，那么tensor.shape.
In [3]: ar = torch.rand(3, 3)
In [4]: ar.shape
Out[4]: torch.Size([3, 3])
# method-1
In [7]: list(ar.shape)
Out[7]: [3, 3]
# method-2
In [8]: [*ar.shape]
Out[8]: [3, 3]
# method-3
In [9]: [*ar.size()]
Out[9]: [3, 3]
P.S.: Note that tensor.shapeis an alias to tensor.size(), though tensor.shapeis an attribute of the tensor in question whereas tensor.size()is a function.
PS：请注意，这tensor.shape是 的别名tensor.size()，尽管tensor.shape是所讨论的张量的属性，而tensor.size()是函数。
