C语言 获取被调用的函数名称作为字符串
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Get called function name as string
提问by Carvallegro
I'd like to display the name of a function I'm calling. Here is my code
我想显示我正在调用的函数的名称。这是我的代码
void (*tabFtPtr [nbExo])(); // Array of function pointers
int i;
for (i = 0; i < nbExo; ++i)
{
printf ("%d - %s", i, __function__);
}
I used __function__as an exemple because it's pretty close from what I'd like but I want to display the name of the function pointed by tabFtPtr [nbExo].
我用作__function__示例是因为它与我想要的非常接近，但我想显示tabFtPtr [nbExo].
Thanks for helping me :)
谢谢你帮助我:)
回答by Lundin
You need a C compiler that follows the C99 standard or later. There is a pre-defined identifier called __func__which does what you are asking for.
您需要遵循 C99 标准或更高版本的 C 编译器。有一个名为的预定义标识符可以满足__func__您的要求。
void func (void)
{
printf("%s", __func__);
}
Edit:
编辑：
As a curious reference, the C standard 6.4.2.2 dictates that the above is exactly the same as if you would have explicitly written:
作为一个奇怪的参考，C 标准 6.4.2.2 规定上述内容与您明确编写的内容完全相同：
void func (void)
{
static const char f [] = "func"; // where func is the function's name
printf("%s", f);
}
Edit 2:
编辑2：
So for getting the name through a function pointer, you could construct something like this:
因此，要通过函数指针获取名称，您可以构造如下内容：
const char* func (bool whoami, ...)
{
const char* result;
if(whoami)
{
result = __func__;
}
else
{
do_work();
result = NULL;
}
return result;
}
int main()
{
typedef const char*(*func_t)(bool x, ...);
func_t function [N] = ...; // array of func pointers
for(int i=0; i<N; i++)
{
printf("%s", function[i](true, ...);
}
}
回答by teppic
I'm not sure this is what you want, but you could do something like this. Declare a structure to hold a function name and address, and an array of functions at file scope:
我不确定这是你想要的，但你可以做这样的事情。声明一个结构来保存函数名称和地址，以及文件范围内的函数数组：
#define FNUM 3
struct fnc {
void *addr;
char name[32];
};
void (*f[FNUM])();
struct fnc fnames[FNUM];
Initialise these in your code manually by function name, e.g.
通过函数名称在您的代码中手动初始化这些，例如
fnames[0] = (struct fnc){foo1, "foo1"}; // function address + its name
fnames[1] = (struct fnc){foo2, "foo2"};
fnames[2] = (struct fnc){foo3, "foo3"};
Make a function to search the array, e.g.
制作一个函数来搜索数组，例如
char *getfname(void *p)
{
for (int i = 0; i < FNUM; i++) {
if (fnames[i].addr == p)
return fnames[i].name;
}
return NULL;
}
I ran a quick test of this. I initialised the array in main, and called foo1(). Here's my function, and the output:
我对此进行了快速测试。我在 中初始化了数组main，然后调用了foo1(). 这是我的函数和输出：
void foo1(void)
{
printf("The pointer of the current function is %p\n", getfnp(__func__));
printf("The name of this function is %s\n", getfname(getfnp(__func__)));
printf("The name of the function at pointer f[2] (%p) is '%s'\n", f[2],
getfname(f[2]));
}
The pointer of the current function is 0x400715
The name of this function is foo1
The name of the function at pointer f[2] (0x40078c) is 'foo3'
Or, more generally:
或者，更一般地说：
void foo2(void)
{
for (int i = 0; i < FNUM; i++) {
printf("Function f[%d] is called '%s'\n", i, getfname(f[i]));
}
}
Function f[0] is called 'foo1'
Function f[1] is called 'foo2'
Function f[2] is called 'foo3'
