java 在java中的特定位置拆分字符串

Splitting a string at a particular position in java

提问by giulio

Assume you have a string of the form "word1 word2 word3 word4". What is the simplest way to split it such that split[0] = "word1 word2"and split[1] = "word3 word4"?

假设您有一个形式为 的字符串"word1 word2 word3 word4"。什么是分裂它使得简单的方法split[0] = "word1 word2"和split[1] = "word3 word4"？

EDIT: Clarifying

编辑：澄清

I want to split such that instead of having split[0] = "word1", I have the first 2 words (I agree it was not clear) and all the other words in split[1], ie on the second space

我想拆分，而不是 split[0] = "word1"，我有前 2 个词（我同意它不清楚）和 split[1] 中的所有其他词，即在第二个空格

回答by Einar Sundgren

I would use the String.substring(beginIndex, endIndex); and String.substring(beginIndex);

我会使用 String.substring(beginIndex, endIndex); 和 String.substring(beginIndex);

String a = "word1 word2 word3 word4";
int first = a.indexOf(" ");
int second = a.indexOf(" ", first + 1);
String b = a.substring(0,second);
String c = b.subString(second); // Only startindex, cuts at the end of the string

This would result in a = "word1 word2" and b = "word3 word4"

这将导致 a = "word1 word2" 和 b = "word3 word4"

回答by ThisClark

Do you want to do this in pairs always? This is a dynamic solution provided by the SO community wiki, Extracting pairs of words using String.split()

你想总是成对地这样做吗？这是 SO 社区维基提供的动态解决方案，使用 String.split() 提取单词对

String input = "word1 word2 word3 word4";
String[] pairs = input.split("(?<!\G\w+)\s");
System.out.println(Arrays.toString(pairs));

output:

输出：

[word1 word2, word3 word4]

回答by TeneCursum

String str = "word1 word2 word3 word4";
String subStr1 = str.substring(0,12);
String subStr2 = str.substring(12);

Would be your best bet for splitting at a position. If you need to split on the second occurrence of space, a for loop might be a better option.

将是您在某个位置拆分的最佳选择。如果您需要在第二次出现空间时拆分，for 循环可能是更好的选择。

int count = 0;
int splitIndex;

for (int i = 0; i < str.length(); i++){
    if(str.charAt(i) == " "){
        count++;
    }
    if (count == 2){
        splitIndex = i;
    }
}

and then you would split it into substrings as above.

然后你会像上面那样将它拆分成子串。

回答by austin wernli

This should do what you want to achieve.

这应该做你想要实现的目标。

You can use String.split(" ");to split on spaces in the initial string.

您可以使用String.split(" ");在初始字符串中的空格处进行拆分。

Then from there you said you wanted the first two words in split[0]so i just handled that with a simple conditional if(i==0 || i == 1) add it to split[0]

然后从那里你说你想要前两个词，split[0]所以我只是用一个简单的条件处理if(i==0 || i == 1) add it to split[0]

String word = "word1 word2 word3 word4";
String[] split = new String[2];
//Split the initial string on spaces which will give you an array of the words.
String[] wordSplit = word.split(" ");
//Foreach item wordSplit add it to either Split[0] or Split[1]
for (int i = 0; i < wordSplit.length(); i++) {
    //Determine which position to add the string to
    if (i == 0 || i == 1) split[0] += wordSplit[i] + " ";
    else {
        split[1] += wordSplit[i] + " ";
    }
}

回答by Russel Peterson

If you would want to split a string into sets of two words, this code could help:

如果您想将字符串拆分为两个单词的集合，此代码可能会有所帮助：

String toBeSplit = "word1 word2 word3 word4";
String firstSplit = a.substr(0,tBS.indexOf(" ", tBS.indexOf(" ")));
String secondSplit = firstSplit.substr(tBS.indexOf(" ", tBS.indexOf(" ")));

回答by sammarcow

Split the string by its common delimiter (spaces in this case) and conditionally re-add the delimiter of choice in output, iterating by 2

通过其公共分隔符（在本例中为空格）拆分字符串，并有条件地在输出中重新添加选择的分隔符，迭代 2

string original = "word1 word2 word3 word4";
string[] delimitedSplit = original.split(" ");
for (int i = 0; i< delimitedSplit.length; i+=2) {
    if (i < delimitedSplit.length - 1 ) { //handle uneven pairs
        out.println(delimitedSplit[i] + " " + delimitedSplit[i+1] ); 
    }
    else {
        out.println(delimitedSplit[i]
    }