xcode 成员引用基类型“int”不是结构或联合
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Member reference base type 'int' is not a structure or union
提问by Itzik984
I have the following code:
我有以下代码：
void setup()
{
address_t sp, pc;
sp = (address_t)stack1 + STACK_SIZE - sizeof(address_t);
pc = (address_t)f;
sigsetjmp(jbuf[0],1);
(jbuf[0]->__jmpbuf)[JB_SP] = translate_address(sp);<----ERROR
(jbuf[0]->__jmpbuf)[JB_PC] = translate_address(pc);<----ERROR
sigemptyset(&jbuf[0]->__saved_mask);<----ERROR
sp = (address_t)stack2 + STACK_SIZE - sizeof(address_t);
pc = (address_t)g;
sigsetjmp(jbuf[1],1);
(jbuf[1]->__jmpbuf)[JB_SP] = translate_address(sp);<----ERROR
(jbuf[1]->__jmpbuf)[JB_PC] = translate_address(pc);<----ERROR
sigemptyset(&jbuf[1]->__saved_mask);<----ERROR
}
Any idea of what this error means?
知道这个错误意味着什么吗？
采纳答案by Michael Burr
The type of a sigjmp_buf(which is what sigsetjmp()takes as a first parameter) is opaque — it's not what your code is expecting it to be in this case. Apparently, it's a simple inthere, not a pointer to a struct.
a 的类型sigjmp_buf（它sigsetjmp()作为第一个参数）是不透明的——在这种情况下它不是你的代码所期望的。显然，int这里很简单，而不是指向结构的指针。
If you want to muck around with the internals of the sigjmp_buf, you'll need to look into how it's implemented on that particular platform (and obviously the code will not be portable).
如果您想处理 的内部结构，则sigjmp_buf需要研究它是如何在该特定平台上实现的（显然代码将不可移植）。
