Java Jackson Json：如何将数组转换为 JsonNode 和 ObjectNode？
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Hymanson Json: how to convert array to JsonNode and ObjectNode?
提问by Stupidfrog
Given Employee and company class
给定 Employee 和 company 类
Company
{
String companyName;
}
Employee
{
String employeeName;
}
and my code like the following
和我的代码如下
List<Employee> e = new ArrayList<Employee>();
.....
.....
i wish i can get result like this
我希望我能得到这样的结果
{
"company":{
"companyName":"cName",
"Employee":[
{"employeeName":"myName1"},
{"employeeName":"myName2"},
{"employeeName":"myName3"}
]
}
}
It is a simple question, however i quite confusing somethings.... Especially Gson And Json....
这是一个简单的问题，但是我很困惑……尤其是 Gson 和 Json ……
Please do not propose other library, which i COMPULSORY NEEDthis library to work. And due to some circumstance,this class IS NOTi wanted.
请不要提出其他图书馆，我强制NEED这个库的工作。由于某些情况，这门课不是我想要的。
Company
{
String companyName;
List<Employee> employees;
}
Therefore i need MANUALLYput it,and serialize to json string.
因此我需要手动放置它，并序列化为 json 字符串。
EDITED:@Sotirios Delimanolis classes declared is the right way to design the relationship between classes. However, that's not i wanted.
编辑：@Sotirios Delimanolis 声明的类是设计类之间关系的正确方法。然而，这不是我想要的。
The Answer from @hsluo is Correct! and same as what @Sotirios Delimanolis mention. Totally fulfill this question.
@hsluo 的回答是正确的！和@Sotirios Delimanolis 提到的一样。完全满足这个问题。
And i did found another way to do it which using Hashmap
我确实找到了另一种使用 Hashmap 的方法
HashMap k = new HashMap();
List<employee> y = new ArrayList<employee>();
y......
k.put("records", y);
k.put("total", total);
and then return to @Responbody, result totally same as @hsluo answered.
然后返回@Responbody，结果与@hsluo 回答完全相同。
AND thanks @Sotirios Delimanolis, @hsluo to help me.
并感谢@Sotirios Delimanolis、@hsluo 帮助我。
采纳答案by hsluo
ObjectMapper mapper = new ObjectMapper();
List<Employee> e = new ArrayList<Employee>();
ArrayNode array = mapper.valueToTree(e);
ObjectNode companyNode = mapper.valueToTree(company);
companyNode.putArray("Employee").addAll(array);
JsonNode result = mapper.createObjectNode().set("company", companyNode);
回答by Sotirios Delimanolis
You can just create a POJO that contains a List<Employee>
您可以只创建一个包含 List<Employee>
class Employees {
@JsonProperty("Employee")
private List<Employee> employees;
public List<Employee> getEmployees() {
return employees;
}
public void setEmployees(List<Employee> employees) {
this.employees = employees;
}
}
and serialize it to an ObjectNode.
并将其序列化为ObjectNode.
Employees e = new Employees();
List<Employee> employees = new ArrayList<Employee>();
e.setEmployees(employees);
ObjectNode objectNode = mapper.valueToTree(e);
回答by transang
You can use Hymanson ObjectNode's putand putArraylike
您可以使用Hyman逊ObjectNode的put和putArray像
import com.fasterxml.Hymanson.databind.node.ObjectNode;
ArrayList<ObjectNode> employee = new ArrayList();
for(int i = 1; i < 4; i++){
ObjectNode em = Json.newObject();
em.put("companyName", "cName" + i);
employee.add(em);
}
ObjectNode company = Json.newObject();
company.put("companyName", "cName");
company.putArray("employee").addAll(employee);
return Json.newObject().put("company", company);
回答by Daniel Alonso
JsonNode result = new ObjectMapper().readTree(e.toString());
