C++ 错误：'int' 之前的预期主表达式
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C++ error: expected primary-expression before ‘int’
提问by Will Gunn
I am getting this error for every int in this section of code;
这部分代码中的每个 int 都会出现此错误；
if(choice==2) {
inssort(int *a, int numLines);
}
if(choice==3) {
bubblesort(int *a, int numLines);
}
if(choice==4) {
mergesort(int *a, int numLines);
}
if(choice==5) {
radixsort(int *a, int numLines);
}
if(choice==6) {
return 0;
}
Thats where I call the functions in main. If you are wondering I am writing a small program that gives the user a choice when sorting a list between 4 different types of sorting algorithms.
这就是我在 main 中调用函数的地方。如果您想知道我正在编写一个小程序，它可以让用户在 4 种不同类型的排序算法之间对列表进行排序时进行选择。
Any help would be appreciated.
任何帮助，将不胜感激。
回答by Mysticial
You can't use the declaration types when you're callingthe functions. Only when you declarethem are they needed:
调用函数时不能使用声明类型。只有当你声明它们时才需要它们：
if(choice==2)
{
inssort(a, numLines);
}
if(choice==3)
{
bubblesort(a, numLines);
}
if(choice==4)
{
mergesort(a, numLines);
}
if(choice==5)
{
radixsort(a, numLines);
}
if(choice==6)
{
return 0;
}
回答by zwol
You're using function declarationsyntax to make function calls. That's not necessary, and (as you have discovered) doesn't even work. You can just write
您正在使用函数声明语法进行函数调用。这不是必需的，而且（正如您所发现的）甚至不起作用。你可以写
if (choice == 2)
inssort(a, numLines);
// etc
By the way, a switchwould be more idiomatic here.
顺便说一句， aswitch在这里会更惯用。
回答by sam
if(choice==2)
{
inssort(int *a, int numLines);
}
your code turn to this
你的代码转向这个
if(choice==2)
{
inssort(&a, numLines);
}
