Javascript Underscore.js，根据键值删除对象数组中的重复项
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Underscore.js, remove duplicates in array of objects based on key value
提问by nikoshr
I have the following JS array:
我有以下 JS 数组：
var myArray = [{name:"Bob",b:"text2",c:true},
{name:"Tom",b:"text2",c:true},
{name:"Adam",b:"text2",c:true},
{name:"Tom",b:"text2",c:true},
{name:"Bob",b:"text2",c:true}
];
I want to eliminate the indexes with name value duplicates and recreate a new array, with distinct names, eg:
我想消除名称值重复的索引并重新创建一个具有不同名称的新数组，例如：
var mySubArray = [{name:"Bob",b:"text2",c:true},
{name:"Tom",b:"text2",c:true},
{name:"Adam",b:"text2",c:true},
];
As you can see, I removed "Bob" and "Tom", leaving only 3 distinct names. Is this possible with Underscore? How?
如您所见，我删除了“Bob”和“Tom”，只留下了 3 个不同的名字。下划线可以做到这一点吗？如何？
回答by nikoshr
With Underscore, use _.uniqwith a custom transformation, a function like _.property('name')would do nicely or just 'name', as @Gruff Bunny noted in the comments :
使用Underscore，_.uniq与自定义转换一起使用，就像@Gruff Bunny 在评论中指出的那样，像_.property('name')这样的函数会做得很好或只是'name'：
var mySubArray = _.uniq(myArray, 'name');
And a demo http://jsfiddle.net/nikoshr/02ugrbzr/
还有一个演示http://jsfiddle.net/nikoshr/02ugrbzr/
If you use Lodashand not Underscore, go with the example given by @Jacob van Lingen in the comments and use _.uniqBy:
如果您使用Lodash而不是Underscore，请使用@Jacob van Lingen 在评论中给出的示例并使用_.uniqBy：
var mySubArray = _.uniqBy(myArray, 'name')
回答by Dexygen
The other answer is definitely best but here's another that's not much longer that also exposes you to more underscore method's, if you're interested in learning:
另一个答案绝对是最好的，但如果您有兴趣学习，这里还有一个不会太长的答案，它也会让您接触更多下划线方法：
var mySubArray = []
_.each(_.uniq(_.pluck(myArray, 'name')), function(name) {
mySubArray.push(_.findWhere(myArray, {name: name}));
})
