wpf 如何将 byte[] 转换为 BitmapImage？
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How can I convert byte[] to BitmapImage?
提问by gerstla
I have a byte[]that represents the raw data of an image. I would like to convert it to a BitmapImage.
我有一个byte[]代表图像的原始数据。我想将其转换为BitmapImage.
I tried several examples I found but I kept getting the following exception
我尝试了几个我发现的例子，但我一直收到以下异常
"No imaging component suitable to complete this operation was found."
“没有找到适合完成此操作的成像组件。”
I think it is because my byte[]does not actually represent an Image but only the raw bits.
so my question is as mentioned above is how to convert a byte[] of raw bits to a BitmapImage.
我认为这是因为我byte[]实际上并不代表图像，而只是代表原始位。所以我的问题如上所述是如何将原始位的字节 [] 转换为BitmapImage.
采纳答案by Clemens
When your byte array contains a bitmap's raw pixel data, you may create a BitmapSource(which is the base class of BitmapImage) by the static method BitmapSource.Create.
当您的字节数组包含位图的原始像素数据时，您可以通过静态方法创建一个BitmapSource（它是 的基类BitmapImage）BitmapSource.Create。
However, you need to specify a few parameters of the bitmap. You must know in advance the width and height and also the PixelFormatof the buffer.
但是，您需要指定位图的一些参数。您必须事先知道PixelFormat缓冲区的宽度和高度以及缓冲区的宽度和高度。
byte[] buffer = ...;
var width = 100; // for example
var height = 100; // for example
var dpiX = 96d;
var dpiY = 96d;
var pixelFormat = PixelFormats.Pbgra32; // for example
var bytesPerPixel = (pixelFormat.BitsPerPixel + 7) / 8;
var stride = bytesPerPixel * width;
var bitmap = BitmapSource.Create(width, height, dpiX, dpiY,
pixelFormat, null, buffer, stride);
回答by Eirik
public static BitmapImage LoadFromBytes(byte[] bytes)
{
using (var stream = new MemoryStream(bytes))
{
stream.Seek(0, SeekOrigin.Begin);
var image = new BitmapImage();
image.BeginInit();
image.StreamSource = stream;
image.EndInit();
return image;
}
}
回答by vapcguy
I ran across this same error, but it was because my array was not getting filled with the actual data. I had an array of bytes that was equal to the length it was supposed to be, but the values were all still 0- they had not been written to!
我遇到了同样的错误，但这是因为我的数组没有填充实际数据。我有一个字节数组，它的长度等于它应该是的长度，但这些值都是静止的0——它们没有被写入！
My particular issue - and I suspect for others that arrive at this question, as well - was because of the OracleBlobparameter. I didn't think I needed it, and thought I could just do something like:
我的特殊问题 - 我怀疑其他人也遇到了这个问题 - 是因为OracleBlob参数。我不认为我需要它，并认为我可以这样做：
DataSet ds = new DataSet();
OracleCommand cmd = new OracleCommand(strQuery, conn);
OracleDataAdapter oraAdpt = new OracleDataAdapter(cmd);
oraAdpt.Fill(ds)
if (ds.Tables[0].Rows.Count > 0)
{
byte[] myArray = (bytes)ds.Tables[0]["MY_BLOB_COLUMN"];
}
How wrong I was! To actually get the real bytes in that blob, I needed to actually read that result into an OracleBlobobject. Instead of filling a dataset/datatable, I did this:
我错了！为了实际获得该 blob 中的实际字节，我需要将该结果实际读入一个OracleBlob对象中。我没有填充数据集/数据表，而是这样做了：
OracleBlob oBlob = null;
byte[] myArray = null;
OracleCommand cmd = new OracleCommand(strQuery, conn);
OracleDataReader result = cmd.ExecuteReader();
result.Read();
if (result.HasRows)
{
oBlob = result.GetOracleBlob(0);
myArray = new byte[oBlob.Length];
oBlob.Read(array, 0, Convert.ToInt32(myArray.Length));
oBlob.Erase();
oBlob.Close();
oBlob.Dispose();
}
Then, I could take myArrayand do this:
然后，我可以采取myArray并做到这一点：
if (myArray != null)
{
if (myArray.Length > 0)
{
MyImage.Source = LoadBitmapFromBytes(myArray);
}
}
And my revised LoadBitmapFromBytesfunction from the other answer:
我LoadBitmapFromBytes在另一个答案中修改过的函数：
public static BitmapImage LoadBitmapFromBytes(byte[] bytes)
{
var image = new BitmapImage();
using (var stream = new MemoryStream(bytes))
{
stream.Seek(0, SeekOrigin.Begin);
image.BeginInit();
image.StreamSource = stream;
image.CreateOptions = BitmapCreateOptions.PreservePixelFormat;
image.CacheOption = BitmapCacheOption.OnLoad;
image.UriSource = null;
image.EndInit();
}
return image;
}
回答by crazylpfan
Create a MemoryStream from the raw bytes and pass that into your Bitmap constructor.
从原始字节创建一个 MemoryStream 并将其传递到您的 Bitmap 构造函数中。
Like this:
像这样：
MemoryStream stream = new MemoryStream(bytes);
Bitmap image = new Bitmap(stream);
