如何更好地控制 Python 中的循环增量？
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How do get more control over loop increments in Python?
提问by efficiencyIsBliss
I'm trying to loop from 0 to 1 using step sizes of 0.01 (for example). How would I go about doing this? The for i in range(start, stop, step)only takes integer arguments so floats won't work.
我正在尝试使用 0.01 的步长（例如）从 0 循环到 1。我该怎么做呢？该for i in range(start, stop, step)只需要整数参数，以便彩车将无法正常工作。
采纳答案by Santa
for i in [float(j) / 100 for j in range(0, 100, 1)]:
print i
回答by efficiencyIsBliss
Well, you could make your loop go from 0 to 100 with a step the size of 1 which will give you the same amount of steps. Then you can divide i by 100 for whatever you were going to do with it.
好吧，你可以让你的循环从 0 到 100，步长为 1，这会给你相同的步数。然后你可以将 i 除以 100，无论你打算用它做什么。
回答by carl
One option:
一种选择：
def drange(start, stop, step):
while start < stop:
yield start
start += step
Usage:
用法：
for i in drange(0, 1, 0.01):
print i
回答by WombatPM
Avoid compounding floating point errors with this approach. The number of steps is as expected, while the value is calculated for each step.
避免使用这种方法复合浮点错误。步数与预期一致，同时计算每个步的值。
def drange2(start, stop, step):
numelements = int((stop-start)/float(step))
for i in range(numelements+1):
yield start + i*step
Usage:
for i in drange2(0, 1, 0.01):
print i
回答by Ganapathy Ramadass
your code
你的代码
for i in range(0,100,0.01):
can be achieved in a very simple manner instead of using float
可以以非常简单的方式实现，而不是使用浮动
for i in range(0,10000,1):
if you are very much concerned with float then you can go with https://stackoverflow.com/a/4935466/2225357
如果您非常关心浮动，那么您可以使用 https://stackoverflow.com/a/4935466/2225357
回答by Ganapathy Ramadass
you can use list comprehensions either:
您可以使用列表推导式：
print([i for i in [float(j) / 100 for j in range(0, 100, 1)]])
if you want control over printing i then do something like so:
如果你想控制打印我然后做这样的事情：
print(['something {} something'.format(i) for i in [float(j) / 100 for j in range(0, 100, 1)]])
or
或者
list(i for i in [float(j) / 100 for j in range(0, 100, 1)])
回答by user2538077
I would say the best way is using numpy array.
我会说最好的方法是使用 numpy 数组。
If you want to to loop from -2 thru +2 with increment of 0.25 then this is how I would do it:
如果您想以 0.25 的增量从 -2 到 +2 循环，那么我将这样做：
Start = -2
End = 2
Increment = 0.25
Array = np.arange(Start, End, Increment)
for i in range(0, Array.size):
print (Array[i])
