PHP - 获取当前 URL
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PHP - Getting Current URL
提问by Howdy_McGee
This seems like a common questions but none of them seem to be what i'm looking for. If there is a website:
这似乎是一个常见的问题，但似乎没有一个是我正在寻找的。如果有网站：
www.example.com/test.php
www.example.com/test.php
I want to pull the "test.php" and if it's something like:
我想拉“test.php”，如果它是这样的：
www.example.com/folder/folder1/test.php
www.example.com/folder/folder1/test.php
I want again to just pull "test.php" but everything seems to pull the exact path instead of just the page. Any suggestions?
我想再次拉“test.php”，但一切似乎都拉出确切的路径，而不仅仅是页面。有什么建议？
回答by Brian Graham
$query = $_SERVER['PHP_SELF'];
$path = pathinfo( $query );
$what_you_want = $path['basename'];
Voila.
瞧。
回答by Tadeck
This will get you the name of the file that was requested (based on the URL invoked, not real location of the file - just in case you are using mod_rewrite):
这将为您提供所请求文件的名称（基于调用的 URL，而不是文件的实际位置 - 以防万一您使用的是 mod_rewrite）：
$filename = basename($_SERVER['REQUEST_URI']);
For both http://www.example.com/testing01.phpand http://www.example.com/x/y/z/testing01.phpwill give you:
对于两者http://www.example.com/testing01.php，http://www.example.com/x/y/z/testing01.php都会给你：
testing01.php
回答by Matt Healy
$file = $_SERVER["SCRIPT_NAME"];
$break = explode('/', $file);
$pfile = $break[count($break) - 1];
