将科学记数法转换为十进制 - python
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Convert scientific notation to decimal - python
提问by pistal
How do I convert a scientific notation to floating point number? Here is an example of what I want to avoid:
如何将科学记数法转换为浮点数？这是我想避免的一个例子：
Python 2.7.3 (default, Apr 14 2012, 08:58:41) [GCC] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> a=[78.40816326530613, 245068094.16326532]
>>> print a[0]/a[1]
3.19944395589e-07
>>> print float(a[0]/a[1])
3.19944395589e-07
>>> print float(a[0])/float(a[1])
3.19944395589e-07
采纳答案by Dhara
The scientific notation is just a convenient way of printing a floating point number. When there are a lot of leading zeros as in your example, the scientific notation might be easier to read.
科学记数法只是一种打印浮点数的便捷方式。当您的示例中有很多前导零时，科学记数法可能更容易阅读。
In order to print a specific number of digits after a decimal point, you can specify a format string with print:
为了在小数点后打印特定数量的数字，您可以使用 print 指定格式字符串：
print 'Number is: %.8f' % (float(a[0]/a[1]))
Or you can use format()as in the other answers.
或者您可以使用format()其他答案。
回答by Ashwini Chaudhary
Use string formatting:
使用字符串格式：
>>> "{:.50f}".format(float(a[0]/a[1]))
'0.00000031994439558937568872208504280885144055446290'
回答by jamylak
That is already a floating point number, it just prints in a friendly format. If you want to show a certain amount of decimal places when printing, use format:
那已经是一个浮点数，它只是以友好的格式打印。如果要在打印时显示一定数量的小数位，请使用format：
>>> print format(a[0]/a[1], '.65f')
0.00000031994439558937568872208504280885144055446289712563157081604
