Java parseInt 与 parseLong
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Java parseInt vs parseLong
提问by aandis
String a = "576055795";
long b = 10*Integer.parseInt(a);
long c = 10*Long.parseLong(a);
System.out.println(b); //Prints 1465590654
System.out.println(c); // Prints 5760557950
Why are they different?
他们为什么不同？
采纳答案by user3553031
Integer.parseInt()returns an int, which is a signed 32-bit integer. 10is also an int; multiplying 576055795by 10as ints overflows and yields an int, which is then promoted to a long.
Integer.parseInt()返回一个int，它是一个有符号的 32 位整数。 10也是一个int; 乘以576055795由10作为整数溢出和产率的int，然后将其提升到一个long。
Long.parseLong()returns a long, which is a signed 64-bit integer. Multiplying it by 10yields a long with no overflow.
Long.parseLong()返回 a long，它是一个有符号的 64 位整数。乘以它会10产生一个没有溢出的 long。
