如何在 C++ 中动态分配指针数组？
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How to dynamically allocate an array of pointers in C++?
提问by Zia ur Rahman
I have the following class
我有以下课程
class Node
{
int key;
Node**Nptr;
public:
Node(int maxsize,int k);
};
Node::Node(int maxsize,int k)
{
//here i want to dynamically allocate the array of pointers of maxsize
key=k;
}
Please tell me how I can dynamically allocate an array of pointers in the constructor -- the size of this array would be maxsize.
请告诉我如何在构造函数中动态分配指针数组——该数组的大小为 maxsize。
回答by
Node::Node(int maxsize,int k)
{
NPtr = new Node*[maxsize];
}
But as usual, you are probably better off using a std::vector of pointers.
但像往常一样，您最好使用 std::vector 指针。
回答by Ashish
Suppose you want to create matrix of 3 rows and 4 cols then,
假设您要创建 3 行 4 列的矩阵，然后，
int **arr = new int * [3]; //first allocate array of row pointers
for(int i=0 ; i<rows ; ++i)
{
arr[i] = new int[4]; // allocate memory for columns in each row
}
回答by Naveen
That will be Nptr = new Node*[maxsize];Also, remember to use delete[]in destructor.
那将Nptr = new Node*[maxsize];也是，记得delete[]在析构函数中使用。
