java JFileChooser 从 JMenu 打开文件
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原文地址: http://stackoverflow.com/questions/15498709/
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JFileChooser to open a file from a JMenu
提问by user2145688
fileItem1is a JMenuItem when i click on fileItem1, this is how you would make it open a file and then just display the name of that file in the JFrame:
当我点击 fileItem1 时，fileItem1 是一个 JMenuItem，这就是你如何让它打开一个文件，然后在 JFrame 中显示该文件的名称：
// open file
fileItem1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
JFileChooser chooser = new JFileChooser();
Component parent = null;
int returnVal = chooser.showOpenDialog(parent);
if(returnVal == JFileChooser.APPROVE_OPTION) {
System.out.println("You chose to open this file: " + chooser.getSelectedFile().getName());
}
jStyledTextPane.setText("You chose to open this file: " + chooser.getSelectedFile().getName());
}
});
采纳答案by oblivion19
The Oracle example is pretty good in my opinion: http://docs.oracle.com/javase/tutorial/uiswing/components/filechooser.html
我认为 Oracle 示例非常好：http: //docs.oracle.com/javase/tutorial/uiswing/components/filechooser.html
Here is the implementation:
这是实现：
int returnVal = fc.showOpenDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//This is where a real application would open the file.
log.append("Opening: " + file.getName() + "." + newline);
} else {
log.append("Open command cancelled by user." + newline);
}
回答by Cugomastik
fileItem1.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent event) {
JFileChooser fc = new JFileChooser();
int returnVal = fc.showOpenDialog(YourClassName.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
filePath = file.getAbsolutePath();
try {
//your write to Jframe method
} catch (FileNotFoundException e) {
Logger.getLogger(YourClassName.class.getName()).log(
Level.SEVERE, null, e);
}
}
}
});
