Java转义JSON字符串？
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Java escape JSON String?
提问by Alosyius
I have the following JSON string that i am sending to a NodeJS server:
我有以下 JSON 字符串要发送到 NodeJS 服务器：
String string = "{\"id\":\"" + userID + "\",\"type\":\"" + methoden + "\",\"msg\":\"" + msget + "\", \"name\":\"" + namnet + "\", \"channel\":\"" + activeChatChannel + "\", \"visitorNick\":\"\", \"agentID\":\" " + agentID + "\"}";
PrintWriter pw = new PrintWriter(new OutputStreamWriter(os, "utf-8"));
pw.println(string);
The problem becomes when the string msgetcontains the character "and '
当字符串的问题变得msget包含字符"和'
On the NodeJS server i am parsing the JSON like this:
在 NodeJS 服务器上，我像这样解析 JSON：
var obj = JSON.parse(message);
Any ideas how i can manage to send all characters without problems?
我有什么想法可以毫无问题地发送所有字符吗？
采纳答案by jabclab
I would use a library to create your JSON Stringfor you. Some options are:
我会使用一个库来String为你创建你的 JSON 。一些选项是：
This will make dealing with escaping much easier. An example (using org.json) would be:
这将使处理逃逸更容易。一个例子（使用org.json）是：
JSONObject obj = new JSONObject();
obj.put("id", userID);
obj.put("type", methoden);
obj.put("msg", msget);
// etc.
final String json = obj.toString(); // <-- JSON string
回答by Silviu Burcea
Try to replace all the " and ' with a \ before them. Do this just for the msget object(String, I guess). Don't forget that \ must be escaped too.
尝试在它们之前用 \ 替换所有 " 和 '。仅针对 msget 对象（我猜是字符串）执行此操作。不要忘记 \ 也必须转义。
回答by Sotirios Delimanolis
回答by Dirk Lachowski
The best method would be using some JSON library, e.g. Hymanson ( http://Hymanson.codehaus.org).
最好的方法是使用一些 JSON 库，例如 Hymanson ( http://Hymanson.codehaus.org)。
But if this is not an option simply escape msget before adding it to your string:
但是，如果这不是一个选项，只需在将其添加到字符串之前转义 msget：
The wrong way to do this is
这样做的错误方法是
String msgetEscaped = msget.replaceAll("\"", "\\"");
Either use (as recommended in the comments)
要么使用（如评论中推荐的那样）
String msgetEscaped = msget.replace("\"", "\\"");
or
或者
String msgetEscaped = msget.replaceAll("\"", "\\\"");
A sample with all three variants can be found here: http://ideone.com/Nt1XzO
可以在此处找到包含所有三种变体的示例：http: //ideone.com/Nt1XzO
回答by Yeongjun Kim
org.json.simple.JSONObject.escape()escapes quotes,, /, \r, \n, \b, \f, \t and other control characters.
org.json.simple.JSONObject.escape()转义引号、、/、\r、\n、\b、\f、\t 和其他控制字符。
import org.json.simple.JSONValue;
JSONValue.escape("test string");
Add pom.xml when using maven
使用maven时添加pom.xml
<dependency>
<groupId>com.googlecode.json-simple</groupId>
<artifactId>json-simple</artifactId>
<scope>test</scope>
</dependency>
回答by orip
Consider Moshi's JsonWriterclass. It has a wonderful API and it reduces copying to a minimum, everything is nicely streamed to the OutputStream.
考虑Moshi的JsonWriter类。它有一个很棒的 API，它将复制减少到最低限度，一切都很好地流式传输到 OutputStream。
OutputStream os = ...;
JsonWriter json = new JsonWriter(Okio.sink(os));
json
.beginObject()
.name("id").value(userID)
.name("type").value(methodn)
...
.endObject();
回答by rhengles
If you want to simply escape a string, not an object or array, use this:
如果您只想转义字符串，而不是对象或数组，请使用以下命令：
String escaped = JSONObject.valueToString(" Quotes \" ' ' \" ");
http://www.json.org/javadoc/org/json/JSONObject.html#valueToString(java.lang.Object)
http://www.json.org/javadoc/org/json/JSONObject.html#valueToString(java.lang.Object)
回答by Ron DeSantis
The JSON specification at https://www.json.org/is very simple by design. Escaping characters in JSON strings is not hard. This code works for me:
https://www.json.org/ 上的 JSON 规范在设计上非常简单。转义 JSON 字符串中的字符并不难。这段代码对我有用：
private String escape(String raw) {
String escaped = raw;
escaped = escaped.replace("\", "\\");
escaped = escaped.replace("\"", "\\"");
escaped = escaped.replace("\b", "\b");
escaped = escaped.replace("\f", "\f");
escaped = escaped.replace("\n", "\n");
escaped = escaped.replace("\r", "\r");
escaped = escaped.replace("\t", "\t");
// TODO: escape other non-printing characters using uXXXX notation
return escaped;
}
回答by Sagar Jadhav
public static String ecapse(String jsString) {
jsString = jsString.replace("\", "\\");
jsString = jsString.replace("\"", "\\"");
jsString = jsString.replace("\b", "\b");
jsString = jsString.replace("\f", "\f");
jsString = jsString.replace("\n", "\n");
jsString = jsString.replace("\r", "\r");
jsString = jsString.replace("\t", "\t");
jsString = jsString.replace("/", "\/");
return jsString;
}
回答by davnicwil
Apache Commons
阿帕奇公地
If you're already using Apache commons, it provides a static method for this:
如果您已经在使用 Apache commons，它会为此提供一个静态方法：
StringEscapeUtils.escapeJson("some string")
It converts any string into one that's properly escaped for inclusion in JSON
它将任何字符串转换为正确转义以包含在 JSON 中的字符串
