php 如何获得以毫秒为单位的时间差
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How to get time difference in milliseconds
提问by jason45
I can't wrap my brain around this one so I hope someone can help. I have a song track that has the song length in milliseconds. I also have the date the song played in DATETIME format. What I am trying to do is find out how many milliseconds is left in the song play time.
我无法解决这个问题，所以我希望有人可以提供帮助。我有一个以毫秒为单位的歌曲长度。我还有歌曲以 DATETIME 格式播放的日期。我想要做的是找出歌曲播放时间还剩多少毫秒。
Example
例子
$tracktime = 219238;
$dateplayed = '2011-01-17 11:01:44';
$starttime = strtotime($dateplayed);
I am using the following to determine time left but it does not seem correct.
我正在使用以下内容来确定剩余时间，但似乎不正确。
$curtime = time();
$timeleft = $starttime+round($tracktime/1000)-$curtime;
Any help would be greatly appreciated.
任何帮助将不胜感激。
采纳答案by Raul Lea?o Martinet
i use the following set of functions for handling mysql dates, maybe they can help you:
我使用以下一组函数来处理 mysql 日期，也许它们可以帮助您：
function sqlArray($date, $trim=true) {
$result = array();
$result['day'] = ($trim==true) ? ltrim(substr($date,8,2),'0') : substr($date,8,2);
$result['month'] = ($trim==true) ? ltrim(substr($date,5,2),'0') : substr($date,5,2);
$result['year'] = substr($date,0,4);
$result['hour'] = substr($date,11,2);
$result['minutes'] = substr($date,14,2);
return $result;
}
function sqlInt($date) {
$date = sqlArray($date);
return mktime($date['hour'], $date['minutes'], 0, $date['month'], $date['day'], $date['year']);
}
function difference($dateStart, $dateEnd) {
$start = sqlInt($dateStart);
$end = sqlInt($dateEnd);
$difference = $end - $start;
$result = array();
$result['ms'] = $difference;
$result['hours'] = $difference/3600;
$result['minutes'] = $difference/60;
$result['days'] = $difference/86400;
return $result;
}
in your case it should be something like:
在你的情况下，它应该是这样的：
$dateplayed = '2011-01-17 11:01:44';
print_r(difference($dateplayed, date('Y:m:d')));
hope it works :D
希望它有效：D
回答by de_niska
For my needs I used the following approach:
根据我的需要，我使用了以下方法：
$curTime = microtime(true);
// something time consuming here
...
// get time difference in milliseconds
$timeConsumed = round(microtime(true) - $curTime,3)*1000;
So, the point is that we use float representation of time here (see http://php.net/manual/en/function.microtime.php)
所以，关键是我们在这里使用时间的浮点表示（参见http://php.net/manual/en/function.microtime.php）
Hope you will adopt it for your needs.
希望您能根据自己的需要采用它。
回答by macha
You could convert the datetime string/input into unixtimestamp and then get the difference. If you do have milliseconds, unixtimestamp would have digits after the decimal. Once you have the difference, you can convert that value back into your date time pattern using function date in php. Below is the link.
您可以将日期时间字符串/输入转换为 unixtimestamp，然后得到差异。如果您确实有毫秒，则 unixtimestamp 将在小数点后包含数字。一旦有了差异，您就可以使用 php 中的函数 date 将该值转换回您的日期时间模式。下面是链接。
Good luck!
祝你好运！
回答by entymon
I used this function for my self:
我为自己使用了这个功能：
public function calculateStringTimeToMiliseconds($timeInString)
{
$startTime = new \DateTime("now");
$endDate = new \DateTime($timeInString);
$interval = $startTime->diff($endDate);
$totalMiliseconds = 0;
$totalMiliseconds += $interval->m * 2630000000;
$totalMiliseconds += $interval->d * 86400000;
$totalMiliseconds += $interval->h * 3600000;
$totalMiliseconds += $interval->i * 60000;
$totalMiliseconds += $interval->s * 1000;
return $totalMiliseconds;
}
回答by Naresh Chennuri
I have written this function to calculate duration between given two timestamps (with milliseconds).
我编写了这个函数来计算给定的两个时间戳（以毫秒为单位）之间的持续时间。
function calculateTransactionDuration($startDate, $endDate)
{
$startDateFormat = new DateTime($startDate);
$EndDateFormat = new DateTime($endDate);
// the difference through one million to get micro seconds
$uDiff = ($startDateFormat->format('u') - $EndDateFormat->format('u')) / (1000 * 1000);
$diff = $startDateFormat->diff($EndDateFormat);
$s = (int) $diff->format('%s') - $uDiff;
$i = (int) ($diff->format('%i')) * 60; // convert minutes into seconds
$h = (int) ($diff->format('%h')) * 60 * 60; // convert hours into seconds
return sprintf('%.6f', abs($h + $i + $s)); // return total duration in seconds
}
$startDate = '02-Mar-16 07.22.13.000548';
$endDate = '02-Mar-16 07.22.14.000072';
$difference = calculateTransactionDuration($startDate, $endDate);
//Outputs 0.999524 seconds
