在 Excel VBA 代码中处理 XMLHttp 响应中的 JSON 对象

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时间:2020-09-03 19:48:51  来源:igfitidea点击:

Handle JSON Object in XMLHttp response in Excel VBA Code

jsonexcelvbaexcel-vbaxmlhttprequest

提问by Santhosh

I need to handle a JSON Object which is the response of XMLHTTPRequest in Excel VBA. I wrote the code below, but it doesn't work:

我需要处理一个 JSON 对象,它是 Excel VBA 中 XMLHTTPRequest 的响应。我写了下面的代码,但它不起作用:

  Dim sc As Object
  Set sc = CreateObject("ScriptControl")
  sc.Language = "JScript"

  Dim strURL As String: strURL = "blah blah"

  Dim strRequest
  Dim XMLhttp: Set XMLhttp = CreateObject("msxml2.xmlhttp")
  Dim response As String

  XMLhttp.Open "POST", strURL, False
  XMLhttp.setrequestheader "Content-Type", "application/x-www-form-urlencoded"
  XMLhttp.send strRequest
  response = XMLhttp.responseText
  sc.Eval ("JSON.parse('" + response + "')")

I am getting the error Run-time error '429' ActiveX component can't create objectin the line Set sc = CreateObject("ScriptControl")

我收到错误运行时错误 '429' ActiveX 组件无法在行中 创建对象Set sc = CreateObject("ScriptControl")

Once we parsed the JSON Object, how do you access the values of the JSON Object?

一旦我们解析了 JSON 对象,您如何访问 JSON 对象的值?

P.S. My JSON Object sample: {"Success":true,"Message":"Blah blah"}

PS我的JSON对象示例: {"Success":true,"Message":"Blah blah"}

采纳答案by Santosh

The code gets the data from nseindia site which comes as a JSON string in responseDivelement.

该代码从 nseindia 站点获取数据,该数据作为responseDiv元素中的 JSON 字符串出现。

Required References

所需参考资料

enter image description here

在此处输入图片说明

3 Class Module i have used

我使用过的 3 个类模块

  • cJSONScript
  • cStringBuilder
  • JSON
  • JSONScript
  • 字符串生成器
  • JSON

(I have picked these class modules from here)

(我从这里选择了这些课程模块)

You may download the file from this link

您可以从此链接下载文件

Standard Module

标准模块

Const URl As String = "http://www.nseindia.com/live_market/dynaContent/live_watch/get_quote/GetQuote.jsp?symbol=ICICIBANK"
Sub xmlHttp()

    Dim xmlHttp As Object
    Set xmlHttp = CreateObject("MSXML2.ServerXMLHTTP.6.0")
    xmlHttp.Open "GET", URl & "&rnd=" & WorksheetFunction.RandBetween(1, 99), False
    xmlHttp.setRequestHeader "Content-Type", "text/xml"
    xmlHttp.send

    Dim html As MSHTML.HTMLDocument
    Set html = New MSHTML.HTMLDocument
    html.body.innerHTML = xmlHttp.ResponseText

    Dim divData As Object
    Set divData = html.getElementById("responseDiv")
    '?divData.innerHTML
    ' Here you will get a string which is a JSON data

    Dim strDiv As String, startVal As Long, endVal As Long
    strDiv = divData.innerHTML
    startVal = InStr(1, strDiv, "data", vbTextCompare)
    endVal = InStr(startVal, strDiv, "]", vbTextCompare)
    strDiv = "{" & Mid(strDiv, startVal - 1, (endVal - startVal) + 2) & "}"


    Dim JSON As New JSON

    Dim p As Object
    Set p = JSON.parse(strDiv)

    i = 1
    For Each item In p("data")(1)
       Cells(i, 1) = item
       Cells(i, 2) = p("data")(1)(item)
        i = i + 1
    Next

 End Sub

回答by Tim Hall

I've had a lot of success with the following library:

我在以下库中取得了很大的成功:

https://github.com/VBA-tools/VBA-JSON

https://github.com/VBA-tools/VBA-JSON

The library uses Scripting.Dictionaryfor Objects and Collectionfor Arrays and I haven't had any issues with parsing pretty complex json files.

该库Scripting.Dictionary用于对象和Collection数组,我在解析非常复杂的 json 文件时没有遇到任何问题。

As for more info on parsing json yourself, check out this question for some background on issues surrounding the JScriptTypeInfo object returned from the sc.Eval call:

至于有关自己解析 json 的更多信息,请查看此问题以了解有关从 sc.Eval 调用返回的 JScriptTypeInfo 对象问题的一些背景知识:

Excel VBA: Parsed JSON Object Loop

Excel VBA:解析的 JSON 对象循环

Finally, for some helpful classes for working with XMLHTTPRequest, a little plug for my project, VBA-Web:

最后,对于一些有用的类XMLHTTPRequest,我的项目 VBA-Web 的一个小插件:

https://github.com/VBA-tools/VBA-Web

https://github.com/VBA-tools/VBA-Web

回答by weeksdev

I know this is an old question but I've created a simple way to interact with Jsonfrom web requests. Where i've wrapped the web request as well.

我知道这是一个老问题,但我创建了一种简单的方法来与JsonWeb 请求进行交互。我也包装了网络请求。

Available here

在这里可用

You need the following code as a class modulecalled Json

您需要以下代码作为class module调用Json

Public Enum ResponseFormat
    Text
    Json
End Enum
Private pResponseText As String
Private pResponseJson
Private pScriptControl As Object
'Request method returns the responsetext and optionally will fill out json or xml objects
Public Function request(url As String, Optional postParameters As String = "", Optional format As ResponseFormat = ResponseFormat.Json) As String
    Dim xml
    Dim requestType As String
    If postParameters <> "" Then
        requestType = "POST"
    Else
        requestType = "GET"
    End If

    Set xml = CreateObject("MSXML2.XMLHTTP")
    xml.Open requestType, url, False
    xml.setRequestHeader "Content-Type", "application/json"
    xml.setRequestHeader "Accept", "application/json"
    If postParameters <> "" Then
        xml.send (postParameters)
    Else
        xml.send
    End If
    pResponseText = xml.ResponseText
    request = pResponseText
    Select Case format
        Case Json
            SetJson
    End Select
End Function
Private Sub SetJson()
    Dim qt As String
    qt = """"
    Set pScriptControl = CreateObject("scriptcontrol")
    pScriptControl.Language = "JScript"
    pScriptControl.eval "var obj=(" & pResponseText & ")"
    'pScriptControl.ExecuteStatement "var rootObj = null"
    pScriptControl.AddCode "function getObject(){return obj;}"
    'pScriptControl.eval "var rootObj=obj[" & qt & "query" & qt & "]"
    pScriptControl.AddCode "function getRootObject(){return rootObj;}"
    pScriptControl.AddCode "function getCount(){ return rootObj.length;}"
    pScriptControl.AddCode "function getBaseValue(){return baseValue;}"
    pScriptControl.AddCode "function getValue(){ return arrayValue;}"
    Set pResponseJson = pScriptControl.Run("getObject")
End Sub
Public Function setJsonRoot(rootPath As String)
    If rootPath = "" Then
        pScriptControl.ExecuteStatement "rootObj = obj"
    Else
        pScriptControl.ExecuteStatement "rootObj = obj." & rootPath
    End If
    Set setJsonRoot = pScriptControl.Run("getRootObject")
End Function
Public Function getJsonObjectCount()
    getJsonObjectCount = pScriptControl.Run("getCount")
End Function
Public Function getJsonObjectValue(path As String)
    pScriptControl.ExecuteStatement "baseValue = obj." & path
    getJsonObjectValue = pScriptControl.Run("getBaseValue")
End Function
Public Function getJsonArrayValue(index, key As String)
    Dim qt As String
    qt = """"
    If InStr(key, ".") > 0 Then
        arr = Split(key, ".")
        key = ""
        For Each cKey In arr
            key = key + "[" & qt & cKey & qt & "]"
        Next
    Else
        key = "[" & qt & key & qt & "]"
    End If
    Dim statement As String
    statement = "arrayValue = rootObj[" & index & "]" & key

    pScriptControl.ExecuteStatement statement
    getJsonArrayValue = pScriptControl.Run("getValue", index, key)
End Function
Public Property Get ResponseText() As String
    ResponseText = pResponseText
End Property
Public Property Get ResponseJson()
    ResponseJson = pResponseJson
End Property
Public Property Get ScriptControl() As Object
    ScriptControl = pScriptControl
End Property

Example Usage (from ThisWorkbook):

示例用法(来自ThisWorkbook):

Sub Example()
    Dim j
    'clear current range
    Range("A2:A1000").ClearContents
    'create ajax object
    Set j = New Json
    'make yql request for json
    j.request "https://query.yahooapis.com/v1/public/yql?q=show%20tables&format=json&callback=&diagnostics=true"
    'Debug.Print j.ResponseText
    'set root of data
    Set obj = j.setJsonRoot("query.results.table")
    Dim index
    'determine the total number of records returned
    index = j.getJsonObjectCount
    'if you need a field value from the object that is not in the array
    'tempValue = j.getJsonObjectValue("query.created")
    Dim x As Long
    x = 2
    If index > 0 Then
        For i = 0 To index - 1
            'set cell to the value of content field
            Range("A" & x).value = j.getJsonArrayValue(i, "content")
            x = x + 1
        Next
    Else
        MsgBox "No items found."
    End If
End Sub