C++ 如何初始化字符串指针？
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how to initialize string pointer?
提问by Dinesh Dabhi
I want to store the static value in string pointer is it posible?
我想将静态值存储在字符串指针中是否可行？
If I do like
如果我喜欢
string *array = {"value"};
the error occurs
错误发生
error: cannot convert 'const char*' to 'std::string*' in initialization
回答by AndersK
you would then need to write
然后你需要写
string *array = new string("value");
although you are better off using
虽然你最好使用
string array = "value";
as that is the intended way to use it. otherwise you need to keep track of memory.
因为这是使用它的预期方式。否则你需要跟踪内存。
回答by juanchopanza
A std::stringpointer has to point to an std::stringobject. What it actually points to depends on your use case. For example:
甲std::string指针具有指向一个std::string对象。它实际指向的内容取决于您的用例。例如：
std::string s("value"); // initialize a string
std::string* p = &s; // p points to s
In the above example, ppoints to a local stringwith automatic storage duration. When it it gets destroyed, anything that points to it will point to garbage.
在上面的示例中，p指向string具有自动存储持续时间的本地。当它被销毁时，任何指向它的东西都将指向垃圾。
You can also make the pointer point to a dynamically allocated string, in which case you are in charge of releasing the resources when you are done:
您还可以使指针指向动态分配的字符串，在这种情况下，您负责在完成后释放资源：
std::string* p = new std::string("value"); // p points to dynamically allocated string
// ....
delete p; // release resources when done
You would be advised to use smart pointersinstead of raw pointers to dynamically allocated objects.
建议您使用智能指针而不是原始指针来动态分配对象。
回答by Rontogiannis Aristofanis
As arrayis an array of strings you could try this:
作为sarray的数组，string你可以试试这个：
int main()
{
string *array = new string[1];
array[1] = "value";
return 0;
}
回答by Jerry Coffin
You can explicitly convert the literal to a string:
您可以将文字显式转换为字符串：
std::string array[] = {std::string("value")};
Note that you have to define this as an array, not a pointer though. Of course, an array mostly makes sense if you have more than one element, like:
请注意，您必须将其定义为数组，而不是指针。当然，如果您有多个元素，则数组通常是有意义的，例如：
string array[] = {string("value1"), string("value2"), string("etc")};
