javascript 使用 KineticJS 从图层中移除对象
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Removing objects from a layer using KineticJS
提问by user1724623
I am currently working a project involving KineticJS.
我目前正在开展一个涉及 KineticJS 的项目。
I have to dynamically create and delete shapes constantly, but cannot seem to figure out how to do the latter. I've been trying to do:
我必须不断地动态创建和删除形状，但似乎无法弄清楚如何做后者。我一直在尝试做：
$ myLayer.remove(myShape)
because this is what most posts seem to recommend. But, the documentation says that this will remove the layer from the stage and not the shape from the layer. When I try this in project it in fact removes the layer from the stage.
因为这是大多数帖子似乎推荐的内容。但是，文档说这将从舞台上删除图层，而不是从图层中删除形状。当我在项目中尝试这个时，它实际上从舞台上删除了图层。
So am I doing something wrong or is there some other way to remove a shape from a layer?
那么我做错了什么还是有其他方法可以从图层中删除形状？
回答by BenMQ
There are two functions that may be helpful.
有两个功能可能会有所帮助。
childContainer.remove()removes the childContainer from it's parent.parentContainer.removeChildren()removes all the children from this container.
childContainer.remove()从其父级中删除 childContainer。parentContainer.removeChildren()从此容器中删除所有子项。
Edit: This can also apply to shapes. Simply redraw the layer.
编辑：这也适用于形状。只需重新绘制图层。
myShape.remove();
myLayer.draw();
回答by Adam Augusta
Somewhere between Kinetic 4.0 and the latest version, remove(child) stopped working. removeChild(child) doesn't work either.
在 Kinetic 4.0 和最新版本之间的某个地方，remove(child) 停止工作。removeChild(child) 也不起作用。
I resolved this problem by using child.remove();
我通过使用 child.remove() 解决了这个问题；
回答by Manjunath Raddi
U can use the prototype of kinetic function
你可以使用动力学函数的原型
Kinetic.Node.prototype.remove.call(removed_object);
Kinetic.Node.prototype.remove.call(removed_object);
baselayer.draw();
baselayer.draw();
