node.js npm "scripts": "start" 运行 express 并打开 url
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Npm "scripts": "start" run express and open url
提问by sreginogemoh
I have this start params in package.json
我有这个开始参数 package.json
"scripts": {
"start": "node bin/www"
},
It is running my express app when I am typing npm start.
当我输入时，它正在运行我的 express 应用程序npm start。
But I want browser opened http://localhost:8081at the same time. How can I say to startto open my local url as well?
但我希望浏览器同时打开http://localhost:8081。我怎么能说start打开我的本地网址呢？
like: "start": "node bin/www, http://localhost:8081"
喜欢： "start": "node bin/www, http://localhost:8081"
So when I am typing npm satrtit runs my express app and opens the url at the same time.
因此，当我输入时，npm satrt它会运行我的 Express 应用程序并同时打开 url。
回答by tylerargo
As far as I know it's like writing a bash command:
据我所知，这就像编写一个 bash 命令：
// Windows
"start":"start http://localhost:8081 & node bin/www"
// Mac
"start":"open http://localhost:8081 && node bin/www"
// Linux
"start":"xdg-open http://localhost:8081 && node bin/www"
回答by pomber
回答by pomber
You just need to use startin the right order!
您只需要按start正确的顺序使用即可！
"start": "npm run dev & start http://localhost:8000",
Bad
坏的
"start": "start http://localhost:8000 & npm run dev",
Good
好的
