如何在python中明智地组合两个numpy数组元素？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/17619415/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How do I combine two numpy arrays element wise in python?
提问by James Mertz
I have two numpy arrays:
我有两个 numpy 数组：
A = np.array([1, 3, 5, 7])
B = np.array([2, 4, 6, 8])
and I want to get the following from combining the two:
我想通过将两者结合起来得到以下内容：
C = [1, 2, 3, 4, 5, 6, 7, 8]
I'm able to get something close by using zip, but not quite what I'm looking for:
我可以通过使用来接近一些东西zip，但不是我正在寻找的东西：
>>> zip(A, B)
[(1, 2), (3, 4), (5, 6), (7, 8)]
How do I combine the two numpy arrays element wise?
如何明智地组合两个 numpy 数组元素？
I did a quick test of 50,000 elements in each array (100,000 combined elements). Here are the results:
我对每个数组中的 50,000 个元素（100,000 个组合元素）进行了快速测试。结果如下：
User Ma3x: Time of execution: 0.0343832323429 Valid Array?: True
User mishik: Time of execution: 0.0439064509613 Valid Array?: True
User Jaime: Time of execution: 0.02767023558 Valid Array?: True
Tested using Python 2.7, Windows 7 Enterprise 64-bit, Intel Core i7 2720QM @2.2 Ghz Sandy Bridge, 8 GB Mem
使用 Python 2.7、Windows 7 Enterprise 64 位、Intel Core i7 2720QM @2.2 Ghz Sandy Bridge、8 GB 内存进行测试
采纳答案by Jaime
回答by mishik
You can try this:
你可以试试这个：
C = sorted(A.tolist() + B.tolist())
A.tolist()will yield[1, 3, 5, 7]B.tolist()will yield[2, 4, 6, 8]A.tolist() + B.tolist()-[1, 3, 5, 7, 2, 4, 6, 8]sorted(...)-[1, 2, 3, 4, 5, 6, 7, 8]
A.tolist()会屈服[1, 3, 5, 7]B.tolist()会屈服[2, 4, 6, 8]A.tolist() + B.tolist()——[1, 3, 5, 7, 2, 4, 6, 8]sorted(...)——[1, 2, 3, 4, 5, 6, 7, 8]
Without sorting:
不排序：
C = [y for x in zip(A, B) for y in x]
回答by Ma3x
Some answers suggested sorting, but since you want to combine them element-wise sorting won't achieve the same result.
一些答案建议排序，但由于您想将它们组合起来，按元素排序不会达到相同的结果。
Here is one way to do it
这是一种方法
C = []
for elem in zip(A, B):
C.extend(elem)
回答by J. Martinot-Lagarde
You can also use slices :
您还可以使用切片：
C = np.empty((A.shape[0]*2), dtype=A.dtype)
C[0::2] = A
C[1::2] = B
回答by gashero
>>> import numpy as np
>>> A=np.array([1,3,5,7])
>>> B=np.array([2,4,6,8])
>>> C=np.dstack([A,B])
>>> D=C.reshape((1,8))[0]
>>> D
array([1, 2, 3, 4, 5, 6, 7, 8])
