Python 不能将序列乘以“float”类型的非整数
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can't multiply sequence by non-int of type 'float'
提问by
level: beginner
水平：初学者
why do i get error "can't multiply sequence by non-int of type 'float'"?
为什么我收到错误“不能将序列乘以'float'类型的非整数”？
def nestEgVariable(salary, save, growthRates):
SavingsRecord = []
fund = 0
depositPerYear = salary * save * 0.01
for i in growthRates:
fund = fund * (1 + 0.01 * growthRates) + depositPerYear
SavingsRecord += [fund,]
return SavingsRecord
print nestEgVariable(10000,10,[3,4,5,0,3])
thanks Baba
谢谢爸爸
采纳答案by Jeremy Brown
for i in growthRates:
fund = fund * (1 + 0.01 * growthRates) + depositPerYear
should be:
应该：
for i in growthRates:
fund = fund * (1 + 0.01 * i) + depositPerYear
You are multiplying 0.01 with the growthRates list object. Multiplying a list by an integer is valid (it's overloaded syntactic sugar that allows you to create an extended a list with copies of its element references).
您将 0.01 乘以增长率列表对象。将列表乘以整数是有效的（它是重载的语法糖，允许您创建带有其元素引用副本的扩展列表）。
Example:
例子：
>>> 2 * [1,2]
[1, 2, 1, 2]
回答by Sam Dolan
You're multipling your "1 + 0.01" times the growthRate list, not the item in the list you're iterating through. I've renamed ito rateand using that instead. See the updated code below:
您将“1 + 0.01”乘以growthRate 列表，而不是您正在迭代的列表中的项目。我已经改名i为rate并使用它。请参阅下面的更新代码：
def nestEgVariable(salary, save, growthRates):
SavingsRecord = []
fund = 0
depositPerYear = salary * save * 0.01
# V-- rate is a clearer name than i here, since you're iterating through the rates contained in the growthRates list
for rate in growthRates:
# V-- Use the `rate` item in the growthRate list you're iterating through rather than multiplying by the `growthRate` list itself.
fund = fund * (1 + 0.01 * rate) + depositPerYear
SavingsRecord += [fund,]
return SavingsRecord
print nestEgVariable(10000,10,[3,4,5,0,3])
回答by Sam Dolan
Because growthRates is a sequence (you're even iterating it!) and you multiply it by (1 + 0.01), which is obviously a float (1.01). I guess you mean for growthRate in growthRates: ... * growthrate?
因为growthRates 是一个序列（您甚至在迭代它！）然后将其乘以(1 + 0.01)，这显然是一个浮点数(1.01)。我猜你的意思是for growthRate in growthRates: ... * growthrate？
回答by Daniel Stutzbach
In this line:
在这一行：
fund = fund * (1 + 0.01 * growthRates) + depositPerYear
I think you mean this:
我想你的意思是：
fund = fund * (1 + 0.01 * i) + depositPerYear
When you try to multiply a float by growthRates (which is a list), you get that error.
当您尝试将浮点数乘以增长率（这是一个列表）时，您会收到该错误。
回答by jathanism
Python allows for you to multiply sequences to repeat their values. Here is a visual example:
Python 允许您将序列相乘以重复它们的值。这是一个视觉示例：
>>> [1] * 5
[1, 1, 1, 1, 1]
But it does not allow you to do it with floating point numbers:
但它不允许你用浮点数来做：
>>> [1] * 5.1
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: can't multiply sequence by non-int of type 'float'
回答by nmichaels
In this line:
在这一行：
fund = fund * (1 + 0.01 * growthRates) + depositPerYear
fund = fund * (1 + 0.01 * growthRates) + depositPerYear
growthRates is a sequence ([3,4,5,0,3]). You can't multiply that sequence by a float (0.1). It looks like what you wanted to put there was i.
增长率是一个序列 ( [3,4,5,0,3])。您不能将该序列乘以浮点数 (0.1)。看起来你想要放在那里的东西是i。
Incidentally, iis not a great name for that variable. Consider something more descriptive, like growthRateor rate.
顺便说一下，i对于那个变量来说，并不是一个好名字。考虑更具描述性的内容，例如growthRate或rate。
