java 使用Jackson将java对象转换为JSON字符串时如何UNESCAPE字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/34706849/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to UNESCAPE String while converting java object to JSON string using Hymanson
提问by gauti
I am using Hymanson version 2.4.3 for converting my complex Java object into String object, so below is what I'm getting in output. The output getting like below (Fyi - I just printed some part of output)
我正在使用 Hymanson 版本 2.4.3 将我的复杂 Java 对象转换为 String 对象，所以下面是我在输出中得到的内容。输出如下(Fyi - I just printed some part of output)
"{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";
Here is my code (PaymentTnx is complex Java object)
这是我的代码（PaymentTnx 是复杂的 Java 对象）
ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
String lpTransactionJSON = mapper.writeValueAsString(paymentTxn);
I don't wanted to see \ slashesh in my JSON string. What I need to do ? Like below:
我不想在我的 JSON 字符串中看到 \ slashesh。我需要做什么 ？像下面这样：
"{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";
回答by gauti
String test = "{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";
System.out.println(StringEscapeUtils.unescapeJava(test));
This might help you.
这可能对你有帮助。
回答by Well Smith
I have not tried Hymanson. I just have similar situation.
我没有试过Hyman逊。我只是有类似的情况。
I used org.apache.commons.text.StringEscapeUtils.unescapeJson but it's not working for malformed JSON format like {\"name\": \"john\"}
我使用了 org.apache.commons.text.StringEscapeUtils.unescapeJson 但它不适用于格式错误的 JSON 格式，例如 {\"name\": \"john\"}
So, I used this class. Perfectly working fine.
所以，我使用了这个类。完美运行。
// BSD License (http://lemurproject.org/galago-license)
package org.lemurproject.galago.utility.json;
public class JSONUtil {
public static String escape(String input) {
StringBuilder output = new StringBuilder();
for(int i=0; i<input.length(); i++) {
char ch = input.charAt(i);
int chx = (int) ch;
// let's not put any nulls in our strings
assert(chx != 0);
if(ch == '\n') {
output.append("\n");
} else if(ch == '\t') {
output.append("\t");
} else if(ch == '\r') {
output.append("\r");
} else if(ch == '\') {
output.append("\\");
} else if(ch == '"') {
output.append("\\"");
} else if(ch == '\b') {
output.append("\b");
} else if(ch == '\f') {
output.append("\f");
} else if(chx >= 0x10000) {
assert false : "Java stores as u16, so it should never give us a character that's bigger than 2 bytes. It literally can't.";
} else if(chx > 127) {
output.append(String.format("\u%04x", chx));
} else {
output.append(ch);
}
}
return output.toString();
}
public static String unescape(String input) {
StringBuilder builder = new StringBuilder();
int i = 0;
while (i < input.length()) {
char delimiter = input.charAt(i); i++; // consume letter or backslash
if(delimiter == '\' && i < input.length()) {
// consume first after backslash
char ch = input.charAt(i); i++;
if(ch == '\' || ch == '/' || ch == '"' || ch == '\'') {
builder.append(ch);
}
else if(ch == 'n') builder.append('\n');
else if(ch == 'r') builder.append('\r');
else if(ch == 't') builder.append('\t');
else if(ch == 'b') builder.append('\b');
else if(ch == 'f') builder.append('\f');
else if(ch == 'u') {
StringBuilder hex = new StringBuilder();
// expect 4 digits
if (i+4 > input.length()) {
throw new RuntimeException("Not enough unicode digits! ");
}
for (char x : input.substring(i, i + 4).toCharArray()) {
if(!Character.isLetterOrDigit(x)) {
throw new RuntimeException("Bad character in unicode escape.");
}
hex.append(Character.toLowerCase(x));
}
i+=4; // consume those four digits.
int code = Integer.parseInt(hex.toString(), 16);
builder.append((char) code);
} else {
throw new RuntimeException("Illegal escape sequence: \"+ch);
}
} else { // it's not a backslash, or it's the last character.
builder.append(delimiter);
}
}
return builder.toString();
}
}
回答by Tassos Bassoukos
This here is not valid JSON:
这在这里不是有效的 JSON：
"{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";
This here is valid JSON, specifically a single string value:
这是有效的 JSON，特别是单个字符串值：
"{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";
Given that you're calling writeValueAsString, this is the correct behaviour. I would suggest writeValue, perhaps?
鉴于您正在调用writeValueAsString，这是正确的行为。我会建议writeValue，也许？
