检查文件是否存在并在 Bash 中继续否则退出
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Check if file exists and continue else exit in Bash
提问by user1190083
I have a script that is one script in a chain of others that sends an email.
我有一个脚本，它是发送电子邮件的一系列其他脚本中的一个。
At the start of the script I want to check if a file exists and continue only if it exists, otherwise just quit.
在脚本开始时，我想检查一个文件是否存在，只有在它存在时才继续，否则就退出。
Here is the start of my script:
这是我的脚本的开始：
if [ ! -f /scripts/alert ];
then
echo "File not found!" && exit 0
else
continue
fi
However I keep getting a message saying:
但是我不断收到一条消息说：
line 10: continue: only meaningful in a `for', `while', or `until' loop
Any pointers?
任何指针？
回答by Kerrek SB
Change it to this:
改成这样：
{
if [ ! -f /scripts/alert ]; then
echo "File not found!"
exit 0
fi
}
A conditional isn't a loop, and there's no place you need to jump to. Execution simply continues after the conditional anyway.
条件不是循环，而且您无需跳转到任何地方。无论如何，执行只是在条件之后继续。
(I also removed the needless &&. Not that it should happen, but just in case the echofails there's no reason not to exit.)
（我也删除了不必要的&&。并不是说它应该发生，但万一echo失败，没有理由不退出。）
回答by Pluckerpluck
Your problem is with the continueline which is normally used to skip to the next iteration of a foror whileloop.
您的问题在于continue通常用于跳到fororwhile循环的下一次迭代的行。
Therefore just removing the elsepart of your script should allow it to work.
因此，只需删除else脚本的一部分即可使其工作。
回答by Kevin
Yes. Drop the else continue. It's entirely unneeded.
是的。放下else continue. 这是完全不需要的。
