Linux 根据文件名模式和文件内容列出文件名？
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List file names based on a filename pattern and file content?
提问by zod
How can I use Grep command to search file namebased on a wild card "LMN2011*"listing all files with this as beginning?
如何使用 Grep 命令file name根据"LMN2011*"列出所有以此开头的文件的通配符进行搜索？
I want to add another check on those file content.
我想对这些文件内容添加另一个检查。
If file contenthas some thing like
如果file content有类似的东西
LMN20113456
Can I use GREPfor this?
我可以用GREP这个吗？
Grep -ls "LMN2011*" "LMN20113456"
What is the proper way to search the file names and its contents using shell commands?
使用 shell 命令搜索文件名及其内容的正确方法是什么？
采纳答案by jm666
Grep DOES NOT use "wildcards" for search – that's shell globbing, like *.jpg. Grep uses "regular expressions" for pattern matching. While in the shell '*' means "anything", in grep it means "match the previous item zero or more times".
Grep 不使用“通配符”进行搜索——这是 shell globbing，比如 *.jpg。Grep 使用“正则表达式”进行模式匹配。在 shell 中，'*' 的意思是“任何东西”，而在 grep 中，它的意思是“匹配前一项零次或多次”。
More information and examples here: http://www.regular-expressions.info/reference.html
更多信息和例子在这里：http: //www.regular-expressions.info/reference.html
To answer of your question - you can find files matching some pattern with grep:
要回答您的问题 - 您可以找到与 grep 匹配某种模式的文件：
find /somedir -type f -print | grep 'LMN2011' # that will show files whose names contain LMN2011
Then you can search their content (case insensitive):
然后你可以搜索他们的内容（不区分大小写）：
find /somedir -type f -print | grep -i 'LMN2011' | xargs grep -i 'LMN20113456'
If the paths can contain spaces, you should use the "zero end" feature:
如果路径可以包含空格，则应使用“零端”功能：
find /somedir -type f -print0 | grep -iz 'LMN2011' | xargs -0 grep -i 'LMN20113456'
回答by Aoife
grep LMN20113456 LMN2011*
or if you want to search recursively through subdirectories:
或者，如果您想通过子目录递归搜索：
find . -type f -name 'LMN2011*' -exec grep LMN20113456 {} \;
回答by ugnelakys
find /folder -type f -mtime -90 | grep -E "(.txt|.php|.inc|.root|.gif)" | xargs ls -l > WWWlastActivity.log
find /folder -type f -mtime -90 | grep -E "(.txt|.php|.inc|.root|.gif)" | xargs ls -l > WWWlastActivity.log
回答by Jahanzeb Farooq
It can be done without findas well by using grep's "--include"option.
它也可以find通过使用 grep 的"--include"选项来完成。
grep man page says:
grep 手册页说：
--include=GLOB
Search only files whose base name matches GLOB (using wildcard matching as described under --exclude).
So to do a recursive search for a string in a file matching a specific pattern, it will look something like this:
因此，要在匹配特定模式的文件中递归搜索字符串，它看起来像这样：
grep -r --include=<pattern> <string> <directory>
For example, to recursively search for string "mytarget" in all Makefiles:
例如，要在所有 Makefile 中递归搜索字符串“mytarget”：
grep -r --include="Makefile" "mytarget" ./
Or to search in all files starting with "Make" in filename:
或者在文件名中以“Make”开头的所有文件中搜索：
grep -r --include="Make*" "mytarget" ./
回答by ohho
Assume LMN2011*files are inside /home/mebut skipping anything in /home/me/tempor below:
假设LMN2011*文件在里面，/home/me但跳过里面/home/me/temp或下面的任何内容：
find /home/me -name 'LMN2011*' -not -path "/home/me/temp/*" -print | xargs grep 'LMN20113456'
