Java 给定LocalDate时如何获得一天的结束时间？
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How to obtain the end of the day when given a LocalDate?
提问by cooxie
How to obtain the end of the day when given a LocalDate?
给定LocalDate时如何获得一天的结束时间？
I could get it by doing
我可以通过做得到它
LocalDateTime.of(LocalDate.now(), LocalTime.of(23, 59, 59));
But is there an equivalent 'atStartOfDay' method for the end of the day?
但是一天结束时是否有等效的“atStartOfDay”方法？
LocalDate.now().atStartOfDay();
LocalDate.now().atEndOfDay(); //doesn't work
采纳答案by assylias
Here are a few alternatives, depending on what you need:
以下是一些替代方案，具体取决于您的需要：
LocalDate.now().atTime(23, 59, 59); //23:59:59
LocalDate.now().atTime(LocalTime.MAX); //23:59:59.999999999
But there is no built-in method.
但是没有内置方法。
As commented by @JBNizet, if you want to create an interval, you can also use an interval up to midnight, exclusive.
正如@JBNizet 所评论的，如果你想创建一个间隔，你也可以使用一个直到午夜的间隔，独占。
回答by TheLostMind
Get start of next day and subtract 1 second from it. This should work for you. :
开始第二天并从中减去 1 秒。这应该对你有用。：
public static void main(String[] args) {
LocalDate date = LocalDate.now();
LocalDateTime dt = date.atStartOfDay().plusDays(1).minusSeconds(1);
System.out.println(dt);
}
O/P :
开/关：
2016-04-04T23:59:59
回答by Robert Hunt
These are the variants available in LocalTime, notice MIDNIGHTand MINare equal.
这些是 中可用的变体LocalTime，注意MIDNIGHT并且MIN是相同的。
LocalDate.now().atTime(LocalTime.MIDNIGHT); //00:00:00.000000000
LocalDate.now().atTime(LocalTime.MIN); //00:00:00.000000000
LocalDate.now().atTime(LocalTime.NOON); //12:00:00.000000000
LocalDate.now().atTime(LocalTime.MAX); //23:59:59.999999999
For reference, this is the implementation in java.time.LocalTime
作为参考，这是在 java.time.LocalTime
/**
* Constants for the local time of each hour.
*/
private static final LocalTime[] HOURS = new LocalTime[24];
static {
for (int i = 0; i < HOURS.length; i++) {
HOURS[i] = new LocalTime(i, 0, 0, 0);
}
MIDNIGHT = HOURS[0];
NOON = HOURS[12];
MIN = HOURS[0];
MAX = new LocalTime(23, 59, 59, 999_999_999);
}
