Python 为列表中的每一项添加一个字符
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add a character to each item in a list
提问by fox
Suppose I have a list of suits of cards as follows:
假设我有一张牌的列表，如下所示：
suits = ["h","c", "d", "s"]
suits = ["h","c", "d", "s"]
and I want to add a type of card to each suit, so that my result is something like
我想为每套花色添加一种卡片，这样我的结果就像
aces = ["ah","ac", "ad", "as"]
aces = ["ah","ac", "ad", "as"]
is there an easy way to do this without recreating an entirely new list and using a forloop?
有没有一种简单的方法可以在不重新创建一个全新的列表和使用for循环的情况下做到这一点？
采纳答案by jamylak
This would have to be the 'easiest' way
这必须是“最简单”的方式
>>> suits = ["h","c", "d", "s"]
>>> aces = ["a" + suit for suit in suits]
>>> aces
['ah', 'ac', 'ad', 'as']
回答by b2Wc0EKKOvLPn
Another alternative, the map function:
另一种选择，地图功能：
aces = map(( lambda x: 'a' + x), suits)
回答by bobrobbob
If you want to add something different than always 'a' you can try this too:
如果你想添加一些不同于 'a' 的东西，你也可以试试这个：
foo = ['h','c', 'd', 's']
bar = ['a','b','c','d']
baz = [x+y for x, y in zip(foo, bar)]
>>> ['ha', 'cb', 'dc', 'sd']
