Java IllegalArgumentException：RestTemplate 没有足够的变量值？
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IllegalArgumentException: Not enough variable values available with RestTemplate?
提问by john
I am trying to execute URL using RestTemplate like this -
我正在尝试使用这样的 RestTemplate 执行 URL -
public static void main(String[] args) throws UnsupportedEncodingException {
RestTemplate restTemplate = new RestTemplate();
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0";
try {
String response = restTemplate.getForObject(url, String.class);
System.out.println(response);
} catch (RestClientException ex) {
ex.printStackTrace();
}
}
But everytime I am getting error like this -
但每次我收到这样的错误 -
Exception in thread "main" java.lang.IllegalArgumentException: Not enough variable values available to expand '@resourceId'
at org.springframework.web.util.UriComponents$VarArgsTemplateVariables.getValue(UriComponents.java:272)
What is wrong I am doing and how to fix it?
我在做什么错以及如何解决？
Update:-
更新：-
I tried with this url as well and it didn't worked for me. I just replaced {@resourceId}with {{@resourceId}}
我也试过这个网址，但对我不起作用。我刚换{@resourceId}了{{@resourceId}}
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{{@resourceId}}?allowScan=true&limit=10000&skip=0";
Update-2
更新 2
Here is the code -
这是代码 -
try {
UriComponentsBuilder builder = UriComponentsBuilder
.fromPath("http://ptr.vip.str.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0");
UriComponents uriComponents = builder.build();
URI uri = uriComponents.toUri();
String response = restTemplate.getForObject(uri, String.class);
System.out.println(response);
} catch (RestClientException ex) {
ex.printStackTrace();
}
And the error is -
而错误是——
Exception in thread "main" java.lang.IllegalArgumentException: URI is not absolute
at java.net.URI.toURL(URI.java:1095)
at org.springframework.http.client.SimpleClientHttpRequestFactory.createRequest(SimpleClientHttpRequestFactory.java:109)
at org.springframework.http.client.support.HttpAccessor.createRequest(HttpAccessor.java:76)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:479)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:460)
at org.springframework.web.client.RestTemplate.getForObject(RestTemplate.java:228)
采纳答案by Sotirios Delimanolis
It doesn't seem like RestTemplatehas a means of ignoring {...}. Instead, generate a URIfrom your Stringvalue (without the double {}).
似乎没有RestTemplate办法忽略{...}. 相反，URI从您的String值生成 a （没有 double {}）。
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0";
UriComponentsBuilder builder = UriComponentsBuilder.fromPath(url);
UriComponents uriComponents = builder.build();
URI uri = uriComponents.toUri();
and use the overloaded getForObjectmethod which takes a URI.
并使用getForObject带有URI.
回答by Richard Xue
U should see the soucre of RestTemplate. The method of getForObject need three parameters,like
你应该看到 RestTemplate 的源代码。getForObject 的方法需要三个参数，比如
public <T> T getForObject(String url, Class<T> responseType, Object... urlVariables)
The 'url' is the part of url's prefix(in front of '?') and 'urlVariables' is a array of parameters.
'url' 是 url 前缀的一部分（在 '?' 之前），'urlVariables' 是一个参数数组。
