在 C# 中更新标签位置？
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Update label location in C#?
提问by avaleske
I have a method that returns a value, and I want this value to be the new location of a label in a windows form application. but I'm being told that a label's location is not a variable. objectA is the name of the label.
我有一个返回一个值的方法，我希望这个值成为 Windows 窗体应用程序中标签的新位置。但有人告诉我标签的位置不是变量。objectA 是标签的名称。
objectA.Location.X = (int)A.position;
objectA.Refresh();
how do I do this?
我该怎么做呢？
采纳答案by Julien Poulin
Use the Leftproperty to change X coordinate of a Label
使用该Left属性更改一个的 X 坐标Label
objectA.Left = 100;
回答by Thomas Levesque
the Location property is of type Point, which is a value type. Therefore, the property returns a copy of the location value, so setting X on this copy would have no effect on the label. The compiler sees that and generates an error so that you can fix it. You can do that instead :
Location 属性属于 Point 类型，这是一种值类型。因此，该属性返回位置值的副本，因此在此副本上设置 X 不会对标签产生影响。编译器会看到并生成错误，以便您可以修复它。你可以这样做：
objectA.Location = new Point((int)A.position, objectA.Location.Y);
(the call to Refresh is useless)
（调用 Refresh 没用）
回答by Alin Vasile
objectA.Location = new Point((int)A.position, objectA.Location.Y);
objectA.Refresh();
Location is no a variable, just a public Property. Changing variables through properties is a bady idea unless you have events that update the parent.
位置不是变量，只是一个公共属性。除非您有更新父级的事件，否则通过属性更改变量是一个坏主意。
回答by RomanT
This works to me
这对我有用
this.label1.Location = new Point(10, 10);
You even do not need to call Refresh or SuspendLayout etc.
您甚至不需要调用 Refresh 或 SuspendLayout 等。
so this should help you
所以这应该可以帮助你
this.label1.Location = new Point((int)A.position, (int)A.otherpos);
回答by Alynuzzu
objectname.Location = System.Drawing.Point(100,100);
objectname.Location = System.Drawing.Point(100,100);
回答by Miguel Angelo
You can only set properties of structs if you have a direct reference to that struct:
如果您直接引用该结构，则只能设置结构的属性：
Point loc = objectA.Location;
loc.X = (int)A.position;
objectA.Location = loc;
