在python列表中找到最小的数字并打印位置
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Find the smallest number in a python list and print the position
提问by Kit Yeung
I have a list of integer imported via a file
我有一个通过文件导入的整数列表
xy = [50, 2, 34, 6, 4, 3, 1, 5, 2]
I am aware of Python: finding lowest integer
However, I wonder how can I print the position of it instead of just finding the smallest number?
但是，我想知道如何打印它的位置而不仅仅是找到最小的数字？
采纳答案by Volatility
Just use the list.indexmethod:
只需使用以下list.index方法：
print xy.index(min(xy))
# 6
If the minimum is repeated, you'll only get the index of the first occurrence, though.
但是，如果重复最小值，则只会获得第一次出现的索引。
回答by sidi
indices = [i for i, x in enumerate(xy) if x == min(xy)] # Indices of all min occurrences
回答by Fahtima
Just in case someone wishes to use for loop:
以防万一有人希望使用 for 循环：
xy = [50, 2, 34, 6, 4, 3, 1, 5, 2]
t=0
for i in range(len(xy)):
if xy[i]<xy[t]:
t=i
print t
