string Scala条带尾随空格
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Scala strip trailing whitespace
提问by Ralph
The Scala Stringmethod (in class StringOps) stripMarginremoves leading whitespace from each line of a multi-line Stringup to and including the pipe (|) character (or other designated delimiter).
ScalaString方法（在 class 中StringOps）stripMargin从多行的每一行中删除前导空格，String直到并包括管道 ( |) 字符（或其他指定的分隔符）。
Is there an equivalent method to remove trailing whitespace from each line?
是否有等效的方法可以从每行中删除尾随空格？
I did a quick look through the Scaladocs, but could not find one.
我快速浏览了 Scaladocs，但找不到。
回答by Daniel C. Sobral
Java Stringmethod trimremoves whitespace from beginning and end:
JavaString方法trim从头到尾删除空格：
scala> println("<"+" abc ".trim+">")
<abc>
回答by kassens
You can easily use a regex for that:
您可以轻松地使用正则表达式：
input.replaceAll("""(?m)\s+$""", "")
The (?m)prefix in the regex makes it a multiline regex. \s+matches 1 or more whitespace characters and $the end of the line (because of the multiline flag).
(?m)正则表达式中的前缀使其成为多行正则表达式。\s+匹配 1 个或多个空白字符和$行尾（由于多行标志）。
回答by user unknown
Split 'n' trim 'n' mkString (like a rock'n'roller):
拆分 'n' 修剪 'n' mkString（就像摇滚乐）：
val lines = """
This is
a test
a foolish
test
a
test
t
"""
lines.split ("\n").map (_.trim).mkString ("\n")
res22: String =
This is
a test
a foolish
test
a
test
t
回答by Ian McLaird
This might not be the most efficient way, but you could also do this:
这可能不是最有效的方法，但您也可以这样做：
val trimmed = str.lines map { s => s.reverse.dropWhile ( c => c == ' ').reverse.mkString(System.getProperty("line.seperator"))
回答by Peter Schmitz
Perhaps: s.lines.map(_.reverse.stripMargin.reverse).mkString("\n")or with System.getProperty("line.separator")instead of "\n"?!
也许：s.lines.map(_.reverse.stripMargin.reverse).mkString("\n")或者用System.getProperty("line.separator")而不是"\n"？！
回答by Det
str.reverse.dropWhile(_ == ' ').reverse
