在 Laravel 4 中返回当前用户
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Return current User in Laravel 4
提问by JasonDavis
Using PHP and Laravel 4 I have a method in my User model like this below to check for Admin user...
使用 PHP 和 Laravel 4 我在我的用户模型中有一个像下面这样的方法来检查管理员用户......
public function isAdmin()
{
if(isset($this->user_role) && $this->user_role === 'admin'){
return true;
}else{
return false;
}
}
This doesn't work when I call this function in other classes or models though.
但是，当我在其他类或模型中调用此函数时，这不起作用。
To get the desired result I had to do it like this instead...
为了得到想要的结果，我不得不这样做......
public function isAdmin()
{
if(isset(Auth::user()->user_role) && Auth::user()->user_role === 'admin'){
return true;
}else{
return false;
}
}
I am trying to access this inside my Admin Controller like this below but it returns an empty User object instead of current logged in user Object...
我试图像下面这样在我的管理控制器中访问它，但它返回一个空的用户对象而不是当前登录的用户对象......
public function __construct(User $user)
{
$this->user = $user;
}
So my question is how can I get the first version to work? When I instantiate a User object in another class, I need to somehow make sure it has the data for the current logged in user but I am not sure the best way to do that...I know this is basic I am just a little rusty right now could use the help, thanks
所以我的问题是如何让第一个版本工作？当我在另一个类中实例化一个 User 对象时，我需要以某种方式确保它具有当前登录用户的数据，但我不确定最好的方法......我知道这是基本的我只是一点点rusty 现在可以使用帮助，谢谢
回答by Laurence
This returns the user repository - not the current logged in user
这将返回用户存储库 - 而不是当前登录的用户
public function __construct(User $user)
To access the current logged in user ANYWHERE in your application - just do
要在您的应用程序中的任何地方访问当前登录的用户 - 只需执行
Auth::user()
(like your middle example)
（就像你的中间例子）
So therefore - to check if a user is an admin user ANYWHERE in your application - just do
因此 - 要检查用户是否是您应用程序中任何地方的管理员用户 - 只需执行
if (Auth::user()->isAdmin())
{
// yes
}
else
{
// no
}
