java 如何为 List 创建 ConstraintValidator

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时间:2020-10-30 21:45:58  来源:igfitidea点击:

how to create a ConstraintValidator for List

javahibernatelistbean-validation

提问by oshai

I have a simple validator to validate that a String value is part of a predefined list:

我有一个简单的验证器来验证字符串值是否是预定义列表的一部分:

public class CoBoundedStringConstraints implements ConstraintValidator<CoBoundedString, String>
{

private List<String> m_boundedTo;

@Override
public void initialize(CoBoundedString annotation)
{
    m_boundedTo = FunctorUtils.transform(annotation.value(), new ToLowerCase());
}

@Override
public boolean isValid(String value, ConstraintValidatorContext context)
{
    if (value == null )
    {
        return true; 
    }

    context.disableDefaultConstraintViolation();
    context.buildConstraintViolationWithTemplate("should be one of " + m_boundedTo).addConstraintViolation();
    return m_boundedTo.contains(value.toLowerCase());
}

}

For example it will Validate:

例如,它将验证:

@CoBoundedString({"a","b" })
public String operations;

I want to create a validator For a list of Strings to validate something like this:

我想为字符串列表创建一个验证器来验证如下内容:

@CoBoundedString({"a","b" })
public List<String> operations = new ArrayList<String>();

I tried this:

我试过这个:

public class CoBoundedStringListConstraints implements ConstraintValidator<CoBoundedString, List<String>>
{

private CoBoundedString m_annotation;

@Override
public void initialize(CoBoundedString annotation)
{
    m_annotation = annotation;
}

@Override
public boolean isValid(List<String> value, ConstraintValidatorContext context)
{
    if (value == null )
    {
        return true; 
    }

    CoBoundedStringConstraints constraints = new CoBoundedStringConstraints();
    constraints.initialize(m_annotation);
    for (String string : value)
    {
        if (!constraints.isValid(string, context))
        {
            return false;
        }
    }
    return true;
}

}

The problem is, if list contains 2 or more illeagal values, there will be only one (the first one) constraint violation. I want it to have more than one. How should I do that?

问题是,如果 list 包含 2 个或更多非法值,则只有一个(第一个)违反约束。我希望它有不止一个。我该怎么做?

采纳答案by jeha

There are 2 problems with your current code:

您当前的代码有两个问题:

In your CoBoundedStringListConstraints's isValidmethod you should iterate over all elements of the given list like this (set a allValidflag appropriate):

在你CoBoundedStringListConstraintsisValid方法中,你应该像这样迭代给定列表的所有元素(设置一个allValid适当的标志):

@Override
public boolean isValid(List<String> value,
        ConstraintValidatorContext context) {
    if (value == null) {
        return true;
    }

    boolean allValid = true;
    CoBoundedStringConstraints constraints = new CoBoundedStringConstraints();
    constraints.initialize(m_annotation);
    for (String string : value) {
        if (!constraints.isValid(string, context)) {
            allValid = false;
        }
    }
    return allValid;
}

The second is the implementation of equalsfor the constraint violation (javax.validation.Validator.validate()returns a set!). When you are always putting in the same message (should be one of [a, b]), the set will still contain only 1 element. As a solution you could prepend the current value to the message (class CoBoundedStringConstraints):

第二个是equals违反约束的实现(javax.validation.Validator.validate()返回一个集合!)。当您始终输入相同的消息 ( should be one of [a, b]) 时,该集合仍将仅包含 1 个元素。作为一种解决方案,您可以将当前值添加到消息(类CoBoundedStringConstraints)中:

@Override
public boolean isValid(String value, ConstraintValidatorContext context) {

    if (value == null) {
        return true;
    }

    if (!m_boundedTo.contains(value)) {
        context.disableDefaultConstraintViolation();
        context.buildConstraintViolationWithTemplate(
                value + " should be one of " + m_boundedTo)
                .addConstraintViolation();
        return false;
    }
    return true;
}